Given:
The equation of a circle is
To find:
The center and radius of the given equation by completing the square.
Solution:
The standard form of a circle is
...(i)
where, (h,k) is center and r is radius of the circle.
We have,
It can be written as
...(ii)
On comparing (i) and (ii), we get
Therefore, the center is and the radius is units.
It should be written in the form ax²+bx+c=0,
so you meed to move -8 to the left side
2x²+6x+8=0
the number in front of x² is a
the number in front of x is b
the number without x is c,
so a=2, b=6,c=8
Answer:
x = 7.9
Step-by-step explanation:
Given:
Angle - 44
Hypotenuse - 11 ft
adjacent side - x
having adjacent and hypotenuse use Cosine to solve the problem from
S-oh C-ah T-oa
cos (angle) = adjacent / hypotenuse
**Make sure your calculator is in degree mode**
cos 44 = x/11
if you cross multiply, you get
11 cos 44 = x
or to solve for x you would multiply both sides by 11 and get
11 cos 44 = x
x = 7.9
The absolute value is always positive:
For example, the absolute value of -5: | - 5 | = 5 and also the absolute value of 5 : | 5 | = 5
P = - 1 1/4
The absolute value of point P.
| P | = | - 1 1/4 | = 1 1/4
Answer:
Thanks but nothing btw do you know BTS?