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Serggg [28]
2 years ago
13

1. SOCCER Suppose a youth soccer field has a

Mathematics
1 answer:
padilas [110]2 years ago
6 0

Answer:

L = 100

W = 60

Step-by-step explanation:

2L + 2W = 320

-2L + 2W = -80

4W = 240

W = 60

L - W = 40

L - 60 = 40

L = 100

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Answer: 0.6

Step-by-step explanation: you divide 3 by 5

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The function given by Upper A left parenthesis t right parenthesis equals 0.0265 t cubed minus 0.444 t squared plus 1.774 t plus
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8 0
3 years ago
One canned orange juice is 25% orange juice another is 5% orange juice. How many liters of each should be mixed together in orde
Cerrena [4.2K]

Answer:

X = \frac{1.6 - 0.05Y}{0.25}= 6.4 -0.2 Y  (3)

Replcaing equation (3) into equation (2) we got:

0.75(6.4 -0.2 Y) +0.95 Y = 18.4

And solving for Y we got:

4.8 -0.15 Y +0.95 Y = 18.4

0.8 Y = 13.6

Y = 17

And solving for X from equation (3) we got:

X= 6.4 -0.2*17 = 3

So we need 3L of orange juice with 25% of concentration and 17 L of orange juice with 5% of concentration

Step-by-step explanation:

For this problem we can work with the concentration of water and orange juice.

Let X the amount for the orange juice with 25% content and Y the amount for the orange juice with 5% of content

Using the concentration of orange juice we have:

0.25 X + 0.05 Y = 20*0.08  (1)

And for the water we have:

0.75 X + 0.95Y = 20*0.92  (2)

If we solve for X from equation (1) we got:

X = \frac{1.6 - 0.05Y}{0.25}= 6.4 -0.2 Y  (3)

Replcaing equation (3) into equation (2) we got:

0.75(6.4 -0.2 Y) +0.95 Y = 18.4

And solving for Y we got:

4.8 -0.15 Y +0.95 Y = 18.4

0.8 Y = 13.6

Y = 17

And solving for X from equation (3) we got:

X= 6.4 -0.2*17 = 3

So we need 3L of orange juice with 25% of concentration and 17 L of orange juice with 5% of concentration

7 0
3 years ago
Which of the following is equivalent to sec2θ−1sec2θ for all values of θ for which sec2θ−1sec2θ is defined?
galina1969 [7]

Answer:

2 sin^2 \theta

Step-by-step explanation:

According to the scenario, the following information is given:

= \frac{sec^2 \theta - 1 }{sec^2 \theta}

= (\frac{1}{\frac{cos^2\theta}{\frac{1}{cos^2\theta} }} - 1)

= 1 - cos^2\theta\\\\= 1 - (1 - 2 sin^2 \theta)\\\\= 2 sin^2 \theta

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5 0
3 years ago
1. What is (6^1/2 x3/4 simplified?
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Answer:

1/ 6

Step-by-step explanation:

5 0
3 years ago
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