P(t)=500(1+4t/(50+t^2 ))
P'(t) = 500 [(50+t^2).4 - 4t.2t]/(50+t^2)^2
by the quotient rule
500 (-4t^2 + 200)/(t^2 + 50)^2
Hence
P'(2) = 500 . (-16 + 200)/54^2 ~= 31.6
Answer:
Total 25.45 hours will be taken to empty the pool.
Step-by-step explanation:
Time taken by large pumpkin to empty the pool=40 hours
Time taken by the smaller pumpkins to empty the pool=70 hours
Amount of pool emptied by large pumpkin in one hour=
Amount of pool emptied by small pumpkin in one hour=
Amount of pool emptied in one hour if both pumpkins work together=
+ 
=
Therefore, the no. of days will be the reciprocal of the amount of work done in one hour ie . 
Total 25.45 hours will be taken to empty the pool.
Answer:
Oh dear, Prodigy?
Step-by-step explanation:
*basically ea math game*
uh let's see...
1.3333333333333 mg
Answer: 10.5 : 20.2
Step-by-step explanation: