If they together at the same rate for the same amount of time, they will solve 48 math problems,
From the question, we can see that two mathletes solve 32 math problems in a certain amount of time, this can be written as:
- 2 mathletes = 32 math problems
In order to determine the number of problems for 3 mathletes, this is expressed as:
DIvide both expressions:
Cross multiply
2x = 3* 32
x = 3 * 16
x = 48math problems
Hence if they together at the same rate for the same amount of time, they will solve 48 math problems,
Learn more on proportion here: brainly.com/question/1496357
V = w*h*l
V = 3*8*4
V = 96 cm^3
One equivalent fraction for 4/21 could be 8/42.
First find the rate of growth using the formula of
A=p e^rt
A 7200
P 6000
E constant
R rate of growth?
T time 6 hours
We need to solve for r
R=[log (A/p)÷log (e)]÷t
R=(log(7,200÷6,000)÷log(e))÷6
R=0.03 rate of growth
Now predict how many bacteria will be present after 17 hours using the same formula
A=p e^rt
A ?
P 6000
R 0.03
E constant
T 17 hours
A=6,000×e^(0.03×17)
A=9,991.7 round your answer to get
A=9992
