All categories

4 years ago

The point (5,-2) is rotated 90° about the origin. Its image is O (-2,5) O (2,5) O (-5,2)

Mathematics

2 answers:

ycow [4]4 years ago

4 0

Answer:

2nd

Step-by-step explanation:

arsen [322]4 years ago

4 0

I do believe it’s (-2,5) :D

You might be interested in

Find the root of the equation below x^2-6x+12=0

Alla [95]

Answer:

Step-by-step explanation:

another word for root are x int.

x^2-6x+12

ac method will not work because there are no real number solutions

you will need to complete the square or use the quadratic formula.

(x-3-sqrt(3i)) (x-3+sqrt(3i))

6 0

3 years ago

Last year,Jim opened an investment account with $7400. At the end of the year, the amount in account had increased by 26.5%. How

KonstantinChe [14]

Step-by-step explanation:

I=prt

I=7400×(26.5/100)×1

I=$1961

total money 7400+1962= $9361

7 0

3 years ago

Divide 1/4 and 3 PLEASE HELP FAST

Eduardwww [97]

Answer:

Step-by-step explanation:

1/4 = .25

3 / .25 = 12

plz mark brainliest if helpful

8 0

4 years ago

Read 2 more answers

In the standard x,y plane, a circle has a radius 6 and center (7, 3). The circle intersects the x-axis at (a, 0) and (b, 0). Wha

arsen [322]

Answer: The required value of a+b is 14.

Step-by-step explanation: Given that in the standard xy plane, a circle has a radius 6 and center (7, 3).

The circle intersects the x-axis at (a, 0) and (b, 0).

We are to find the value of a+b.

We know that

the standard equation of a circle with center at (h, k) and radius r units is given by

$(x-h)^2+(y-k)^2=r^2~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

For the given circle, we have

(h, k) = (7, 3) and r = 6 units.

So, from equation (i), we get

$(x-7)^2+(y-3)^2=6^2\\\\\Rightarrow (x-7)^2+(y-3)^2=36~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)$

Since the circle (ii) passes through the points (a, 0) and (b, 0), so let the point be denoted by (c, 0), then we have

$(c-7)^2+(0-3)^2=36\\\\\Rightarrow (c-7)^2+9=36\\\\\Rightarrow (c-7)^2=27\\\\\Rightarrow c-7=\pm3\sqrt3~~~~~~~~~~~~~~~~~~~~~~[\textup{Taking square root on both sides}]\\\\\Rightarrow c=7\pm3\sqrt3$

Therefore, we get

$a=7+3\sqrt3,\\\\b=7-3\sqrt3.$

That is,

$a+b=(7+3\sqrt3)+(7-3\sqrt3)=14.$

Thus, the required value of a+b is 14.

4 0

3 years ago

What is the solution to to the equation x − 2/5 = −1?

ZanzabumX [31]

Answer:

x = -0.6

Step-by-step Solution:

<u>Isolate the variable x to get the answer.</u>

x − 2/5 = −1
=> x = -1 + 2/5
=> x = -1 + 0.4
=> x = -0.6

Hence, the value of x is -0.6.

6 0

2 years ago

Read 2 more answers