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mamaluj [8]
3 years ago
5

What’s the answer to this problem and how do you figure it out.

Mathematics
1 answer:
tatuchka [14]3 years ago
3 0
To solve this, take a look at the images provided and first find out the number of polygons out of the total number of cards given which would be 3 polygons out of 5 cards, which would be better represented as the fraction 3/5. Now, the question asks to find the probability of Julie picking a card that shows a polygon, and since 3 out of 5 of the cards are polygons, your answer would be 3/5.
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Prove that the sum of three consecutive integers is divisible by 3
11111nata11111 [884]

Answer:

n+n+1+n+2=3n+3=3(n+1)

Step-by-step explanation:

4 0
3 years ago
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Find missing term w+9/6=12​
Sladkaya [172]

Answer: The missing term for W is 10.5.

Step-by-step explanation:

W + 9/6 = 12

W +9/6 - 9/6 = 12- 9/6

W = 12 - 1.5

W = 10.5

3 0
3 years ago
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Convert the equation into slope-intercept form 2x+3y=9
SVETLANKA909090 [29]
Convert the equation into slope-intercept form 2x+3y=9

8 0
3 years ago
Many elementary school students in a school district currently have ear infections. A random sample of children in two different
Marta_Voda [28]

Answer:

Step-by-step explanation:

The summary of the given data includes;

sample size for the first school n_1 = 42

sample size for the second school n_2  = 34

so 16 out of 42 i.e x_1 = 16 and 18 out of 34 i.e x_2 = 18 have ear infection.

the proportion of students with ear infection Is as follows:

\hat p_1 = \dfrac{16}{42} = 0.38095

\hat p_2 = \dfrac{18}{34}  =  0.5294

Since this is a two tailed test , the null and the alternative hypothesis can be computed as :

H_0 :p_1 -p_2 = 0 \\ \\ H_1 : p_1 - p_2 \neq 0

level of significance ∝ = 0.05,

Using the table of standard normal distribution, the value of z that corresponds to the two-tailed probability 0.05 is 1.96. Thus, we will reject the null hypothesis if the value of the test statistics is less than -1.96 or more than 1.96.

The test statistics for the difference in proportion can be achieved by using a pooled sample proportion.

\bar p = \dfrac{x_1 +x_2}{n_1 +n_2}

\bar p = \dfrac{16 +18}{42 +34}

\bar p = \dfrac{34}{76}

\bar p = 0.447368

\bar p + \bar  q = 1 \\ \\ \bar q = 1 -\bar  p \\  \\\bar q = 1 - 0.447368 \\ \\\bar q = 0.552632

The pooled standard error can be computed by using the formula:

S.E = \sqrt{ \dfrac{ \bar p \bar q}{ n_1} +  \dfrac{\bar p \bar p}{n_2} }

S.E = \sqrt{ \dfrac{  0.447368 *  0.552632}{ 42} +  \dfrac{ 0.447368 *  0.447368}{34} }

S.E = \sqrt{ \dfrac{  0.2472298726}{ 42} +  \dfrac{ 0.2001381274}{34} }

S.E = \sqrt{ 0.01177284105}

S.E = 0.1085

The test statistics is ;

z = \dfrac{\hat p_1 - \hat p_2}{S.E}

z = \dfrac{0.38095- 0.5294}{0.1085}

z = \dfrac{-0.14845}{0.1085}

z = - 1.368

Decision Rule: Since the test statistics is greater than the rejection region - 1.96 , we fail to reject the null hypothesis.

Conclusion: There is insufficient evidence to support the claim that a difference exists between the proportions of students who have ear infections at the two schools

5 0
3 years ago
Are all negative numbers really 0
algol13

Answer:

Thus every real number other than zero is either positive or negative, while zero itself is not considered to have a sign. Positive numbers are sometimes written with a plus sign in front, e.g. +3 denotes a positive three.

7 0
2 years ago
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