Answer:
#include <iostream>
using namespace std;
int main() {
int a[4][5];//declaring a matrix of 4 rows and 5 columns.
for(int i=0;i<4;i++)
{
for(int j=0;j<5;j++)
{
if(i==3)//initializing last row as 0.
{
a[i][j]=0;
}
else//initializing last row as 1.
{
a[i][j]=1;
}
}
}
for(int i=0;i<4;i++)
{
for(int j=0;j<5;j++)
cout<<a[i][j]<<" ";//printing the matrix.
cout<<endl;
}
return 0;
}
Output:-
1 1 1 1 1
1 1 1 1 1
1 1 1 1 1
0 0 0 0 0
Explanation:
I have created a matrix of size 4 rows and 5 columns.I have used for loops to fill the array.To fill the last row with 0 i have used if statement.else we are filling it with 1.
Answer:
There are 3 Data Hazard
Explanation:
Find attached the solution
Answer:
E-book : online edition of a new novel .
e-zine:online issue of today’s newspaper.
Online reference: online encyclopedia
blog: online website that posts restaurants reviews
Explanation:
Are you doing edge?
Also pleaseeeeeeeeeeeeeeeeeee mark me brainliest.
What are ur possible answers
Answer:
A. the museum can choose a heuristic approach which will achieve a lossless compression, but they cannot be sure that it is the most efficient compression for each image
C. algorithms for lossless compression exist, so the museum can use those to compress the image
Explanation:
