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Marta_Voda [28]
1 year ago
15

Describe the method used by operating systems to differentiate between TCP connections.

Computers and Technology
1 answer:
Ksivusya [100]1 year ago
8 0

The operating systems differentiate TCP connections only if   two programs are said to be not able to access the "same port." For the aim of TCP, a connection is known to be defined by the use of tuple such as (src_ip,src_port,dst_ip,dst_port). Hence, the OS can be able to note or see those are a kind of  different "connections" and can be able to push the packets to the right socket objects.

<h3>What are TCP connections?</h3>

TCP is known to be a kind of a connection-oriented, and it is also a kind of linkage or connection that is said to exist between client and server which is said to be set up before data can be sent.

Note that the server is one that need to be listening (that is passively open) for any form of connection requests from any clients before the said connection is said to be established.

Hence, The operating systems differentiate TCP connections only if   two programs are said to be not able to access the "same port." For the aim of TCP, a connection is known to be defined by the use of tuple such as (src_ip,src_port,dst_ip,dst_port). Hence, the OS can be able to note or see those are a kind of  different "connections" and can be able to push the packets to the right socket objects.

Learn more about operating systems from

brainly.com/question/22811693

#SPJ1

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Write a program that reads a string consisting of a positive integer or a positive decimal number and converts the number to the
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Answer:

#include <iostream>

#include <string>

#include <stack>

#include <math.h>

using namespace std;

int main() {

  string s;

  double n=0;

  int position=0;  

  stack<int> wholeNumbers;

  cout<<"Enter a decimal number:";

  cin>>s;

  string::iterator counter = s.begin();

  while(*counter!='.' && counter!=s.end()){

      wholeNumbers.push(*counter-48);

      counter++;

      position=position+1;

     

  }

  for(int i=0;i<position;i++){

      n=n+(wholeNumbers.top()*pow(10,i));

      wholeNumbers.pop();

  }

  position=-1;

  if(counter!=s.end()){

      counter++;

  }

  while(counter!=s.end()){

      n=n+((*counter-48)*pow(10,position));

      position=position-1;

      counter++;      

  }

  cout<<n;

}

Explanation:

  • Inside the while loop, push the push a number to the wholeNumbers stack by subtracting it with 48.
  • Increment the counter and position variable by 1 inside the while loop.
  • Count the number of digit, push each digit to top of stack and find the end of the number,
  • Run a for loop up to the value of position variable and pop a value from the wholeNumbers stack.
5 0
4 years ago
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