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Rom4ik [11]
3 years ago
9

Renee spent 1/8 of the day landscaping around the house. She spent half of the time pulling weeds. What fraction of the day did

rehne spend pulling weeds?
Mathematics
1 answer:
Inga [223]3 years ago
8 0

Answer:

The fraction of the day Rehee spent pulling weeds = 1/16

Step-by-step explanation:

Let us take the fraction representing a whole day to be a whole number - 1

Renee spent 1/8 of the day landscaping around the house.

This means she spent 1/8 X 1 landscaping around the house = 1/8

She spent half of the time pulling weeds.

This means she spent 1/2 of 1/8 of  1 landscaping around the house = 1/16

1/2 X 1/8 X 1 = 1/16

The fraction of the day Rehee spent pulling weeds = 1/16

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£220 is invested at 3% pa simple work out the interest for 8 years.
Svetllana [295]

Answer:

The answer is £52.8

Step-by-step explanation:

4 0
3 years ago
200m - 100m + 48,250 = 50,250 – 150m
drek231 [11]

200m - 100m + 48,250 = 50,250 - 150m

(Add or subtract common variables)

100m + 48,250 = 50,250 - 150m

(Add 150m to both sides)

250m + 48,250 = 50,250

(Subtract 48,250 to both sides)

250m = 2000

(Divide 250 to both sides to isolate m)

m = 8

5 0
3 years ago
The table below shows the relative frequencies for part-time and full-time employees at Companies
user100 [1]

Answer: 83%

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8 0
3 years ago
Enrique and Yolanda collected 500 pieces of candy on Halloween. they gave half of their candy to charity. Yolanda took 180 piece
Ivenika [448]

500 − 250  = 250 pieces left after donation

Yolanda got  180 pieces....then Enrique  got 70 pieces

So he got   70 /250  = 7/25  =  28%  of the remaining candy

4 0
3 years ago
A rectangular garden has an area of 24 square meters. The width is 8 meters less than twice the length. Find the dimensions of t
OLEGan [10]

Answer:

Length: 6 m

Width: 4 m

Step-by-step explanation:

Area: 24 m^{2}

Width: 2L - 8 m

Length: ?

Formula: A = W * L

Replace the variables:

24 = (2L - 8) * L

24 = 2L^{2} - 8L

0 = 2L^{2} - 8L - 24

or

2L^{2} - 8L - 24 = 0

Solve; if you don't know how to solve it using this method, let me know. It's the expression Ax^{2} +Bx+C

1. 2 (\frac{(2L^2 - 8L - 24)}{2})

2. \frac{(2L)^2 - 8(2L) - 48}{2}

3. \frac{(2L - 12)(2L + 4)}{2}

4. 2(\frac{(L - 6)(2L + 4)}{2})

5. (L-6) (2L+4)

6. L-6 = 0 AND 2L+4 = 0

L - 6 =0

L = 6

---------------------------------

2L = -4

L = \frac{-4}{2}

L = -2

Since the length cannot be negative, the only real value is 6.

Area: 24 m^{2}

Width: 2L - 8 m

Length: 6 m

Calculate width:

W = 2L - 8

W = 2(6) - 8

W = 12 - 8

W = 4 m

3 0
3 years ago
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