Answer:
B) 190 cm^2
forgive me if I am wrong.
Step-by-step explanation:
=11/3×1/14
=3.67×0.07
=0.2568
<u>7x + 3 = 9x - 7</u>
Subtract 7x from each side: + 3 = 2x - 7
Add 7 to each side: 10 = 2x
Divide each side by 2 : <em>5 = x </em>
Kid-A A1,A2,A3,A4,A5
Kid-B B1,B2,B3,B4,B5
Kid-C C1,C2,C3,C4,C5
Kid-D D1,D2,D3,D4,D5
Ellen E1,E2,E3,E4,E5
<h3>
Answer: Approximately 6.58 years old</h3>
The more accurate value is 6.57881347896059, which you can round however you need. I picked two decimal places.
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Explanation:
Let's pick a starting value of the car. It doesn't matter what the starting value, but it might help make the problem easier. Let's say A = 1000. Half of that is 1000/2 = 500.
So we want to find out how long it takes for the car's value to go from $1000 to $500 if it depreciates 10% per year.
The value of r is r = 0.10 as its the decimal form of 10%
t is the unknown number of years we want to solve for
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y = A(1 - r)^t
500 = 1000(1 - 0.1)^t
500 = 1000(0.9)^t
1000(0.9)^t = 500
0.9^t = 500/1000
0.9^t = 0.5
log( 0.9^t ) = log( 0.5 )
t*log( 0.9 ) = log( 0.5 )
t = log( 0.5 )/log( 0.9 )
t = 6.57881347896059
Note the use of logs to help us isolate the exponent.
