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Nadusha1986 [10]
2 years ago
14

1/1

Mathematics
1 answer:
erma4kov [3.2K]2 years ago
4 0

Answer:

$15.56

Step-by-step explanation:

So start by doing a 10% tip, because you just move the decimal place over by 1, so $1.35, and then divide that by 2 to get 5% which is .68, and add them to get 2.03. You can get the same answer by multiplying 0.15 to 13.53. 13.53 + 2.03 is 15.56. Hope this helped and have an awesome day!

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Solve the equation: Sin2x - Sinx = 0
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We know that sin2x=2sinxcosx 
(search the net for proof if you wish) 

So the original equation becomes

2sinxcosx-sinx=0
The two terms both have sinx that can be taken out to get: 

sinx(2cosx-1)=0 
This is true if sinx=0 or 2cosx-1=0 , rewritten: cosx=1/2

sinx=0 than x=2kπ
cosx=1/2 than x=π/3+2kπ
where k is an integer

5 0
3 years ago
Karen and Bill collect coins. Karen has x coins. Bill has 9 coins fewer than two times the number of coins Karen has. Write and
Eduardwww [97]
Karen = x
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6 0
2 years ago
Please Help, and show work..
azamat
Hi there! So the the new price is $93, and went up from $55. Let's subtract the numbers. 93 - 55 is 38. The change is 38. To find the percent markup, we can write and solve a proportion. Set it up like this:

38/55 = x/100

This is because the amount of change goes above the original (55), and x represents the percent out of 100. We are looking for the markup. Let's cross multiply the values. 100 * 38 is 3,800. 55 * x is 55x. 3,800 = 55x. Now, divide each side by 55 to isolate the x. 55x/55 cancels out. 3,800/55 is 69.0909 or 69 when rounded to the nearest whole number. There. The percent of markup is approx. 69%.
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3 years ago
The base of a garden box has an area of 27,404 square centimeters. It's height is 18 centimeters. What is the volume of the gard
taurus [48]

6

What do AIA, SAG, AFP and AMA all stand for? Select four options.

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6 0
2 years ago
Find a nonzero vector orthogonal to the plane through the points: ????=(0,0,1), ????=(−2,3,4), ????=(−2,2,0).
ser-zykov [4K]

Answer:

The nonzero vector orthogonal to the plane is <-9,-8,2>.

Step-by-step explanation:

Consider the given points are P=(0,0,1), Q=(−2,3,4), R=(−2,2,0).

\overrightarrow {PQ}==

\overrightarrow {PR}==

The nonzero vector orthogonal to the plane through the points P,Q, and R is

\overrightarrow n=\overrightarrow {PQ}\times \overrightarrow {PR}

\overrightarrow n=\det \begin{pmatrix}i&j&k\\ \:\:\:\:\:-2&3&3\\ \:\:\:\:\:-2&2&-1\end{pmatrix}

Expand along row 1.

\overrightarrow n=i\det \begin{pmatrix}3&3\\ 2&-1\end{pmatrix}-j\det \begin{pmatrix}-2&3\\ -2&-1\end{pmatrix}+k\det \begin{pmatrix}-2&3\\ -2&2\end{pmatrix}

\overrightarrow n=i(-9)-j(8)+k(2)

\overrightarrow n=-9i-8j+2k

\overrightarrow n=

Therefore, the nonzero vector orthogonal to the plane is <-9,-8,2>.

8 0
3 years ago
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