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Alecsey [184]
2 years ago
15

your current wardrobe consists of eleven different items: three pairs of shoes, two pairs of pants, and six different shirts. yo

ur mom offered to buy you a new shirt or a new pair of shoes. which item (shoes or shirt) should your mom buy for you to maximize your total number of outfits (shoesshirt-pant)?
Mathematics
1 answer:
Alex73 [517]2 years ago
6 0

<u>A </u><u>pair of shoes</u><u> gives us</u><u> 48 </u><u>different outfits.</u>

What is a linear equation?

  • A linear equation is an algebraic equation of the form y=mx+b, where m is the slope and b is the y-intercept, and only a constant and a first-order (linear) term are included.
  • The variables in the preceding equation are y and x, and it is occasionally referred to as a "linear equation of two variables." from Wolfram MathWorld: linear

We will employ the basic counting principle, which states that if one task can be completed in method A and another in way B, then both tasks may be completed in way A*B.

If mom buys 1 shirt, then total shirts(A) = 6+1 =7, total pants(B) = 2 and total shoes (C) = 3

By basic counting principle, number of outfits = A*B*C = 7*2*3 = 42 outfits possible

and

If mom buys 1 pair of shoes, then total shirts(A) = 6, total pants(B) = 2 and total shoes (C) = 3+1 = 4

By basic counting principle, number of outfits = A*B*C = 6*2*4 = 48 outfits possible

hence, buying a pair of shoes gives us 48 different outfits.

Learn more about linear equation

brainly.com/question/11897796

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7 . Sampling distribution of the difference between two means A statistician is interested in the effectiveness of a weight-loss
UkoKoshka [18]

Answer:

0.229

Step-by-step explanation:

Given that the difference between the two sample means follows anormal distribution with a mean of11.00 and standard deviation equal to1.4387

A statistician is interested in the effectiveness of a weight-loss supplement. She randomly selects two independent samples. Individuals in the first sample of size n1 = 24 take the weight-loss supplement. Individuals in the second sample of size n2 = 21 take a placebo. Individuals in both samples follow identical exercise and diet programs. At the end of the study, the statistician measures the weight loss (in percent) of each participant.

We find that mean difference actual = 13-2 = 11

Probability that difference >12 =P(Z>\frac{12-11}{1.3487} \\)

=P(Z>0.742)=.0.229

3 0
3 years ago
Combine like terms to create an equivalent expression.
Brut [27]

Question..

Combine like terms to create an equivalent expression.

½ −⅙q +⅚q - ⅓

Answer:

½ −⅙q +⅚q - ⅓ is equivalent to ⅔q + ⅙

Step-by-step explanation:

Given

½ −⅙q +⅚q - ⅓

Required

Equivalence

½ −⅙q +⅚q - ⅓

We start by collecting like terms.

⅚q - ⅙q + ½ - ⅓

Factorize

(⅚ - ⅙)q + ½ - ⅓

((5 - 1)/6)q + ½ - ⅓

(4/6)q + ½ - ⅓

Reduce 4/6 to lowest term

⅔q + ½ - ⅓

Evaluate fraction

⅔q + (3 - 2)/6

⅔q + ⅙

Hence, ½ −⅙q +⅚q - ⅓ is equivalent to ⅔q + ⅙

7 0
3 years ago
Read 2 more answers
what is the prime factorization of 55^5 x 65 x 9^15 and why? A. 3^15 * 5^6 *11^5*13 B. 3^30 *5^6 *11^5 *13 C.3^30 * 5^6 *11 * 13
leonid [27]

Answer:

B

Step-by-step explanation:

1. Lets focus on 55^5

55^5 = 11^5 * 5^5

2. now on 65

65 = 5 * 13

3. now on 9^15

9^15=(3^2)^15 = 3^30

4. combine all three parts

11^5 * 5^5 * 5 * 13 * 3^30 = 11^5*5^6*13*3^30

so our answer is B

7 0
3 years ago
The amount of chlorine in a swimming pool is proportional to the volume of water. The pool has 2.5 milligrams of chlorine per li
stira [4]

Answer:

There are <u>20,000 milligrams</u> chlorine in the pool.

Step-by-step explanation:

Given:

The chlorine per liter of water in the pool is 2.5 milligrams.

The  volume of water in the swimming pool is 8000 gallons.

Now, to find the quantity of chlorine in the pool.

Let the quantity of chlorine be x.

The gallons of water in the swimming pool = 8000.

The milligrams of chlorine per liter of water in the pool = 2.5.

According to question, the amount of chlorine in the swimming pool is proportional to the volume of water.

So, 2.5 mg of chlorine is equivalent to 1 liter.

Thus, x is equivalent to 8000.

Now, to get the quantity of chlorine by using cross multiplication method:

\frac{2.5}{1} =\frac{x}{8000}

<em>By cross multiplying we get:</em>

20000=x\\\\x=20,000\ mg.

Therefore, there are 20,000 milligram chlorine in the pool.

6 0
3 years ago
Can someone please HELP ME
nirvana33 [79]

a) the independent variable is the number of training miles.

b) the dependent variable is the cost to mail the package

c) the dependent variable is P

3 0
3 years ago
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