Answer:
0.30
Step-by-step explanation:
Probability of stopping at first signal = 0.36 ;
P(stop 1) = P(x) = 0.36
Probability of stopping at second signal = 0.54;
P(stop 2) = P(y) = 0.54
Probability of stopping at atleast one of the two signals:
P(x U y) = 0.6
Stopping at both signals :
P(xny) = p(x) + p(y) - p(xUy)
P(xny) = 0.36 + 0.54 - 0.6
P(xny) = 0.3
Stopping at x but not y
P(x n y') = P(x) - P(xny) = 0.36 - 0.3 = 0.06
Stopping at y but not x
P(y n x') = P(y) - P(xny) = 0.54 - 0.3 = 0.24
Probability of stopping at exactly 1 signal :
P(x n y') or P(y n x') = 0.06 + 0.24 = 0.30
Answer:
I think it could be 8+6+y
Step-by-step explanation: I dont really know but dont delete this. Can I be Brainlyest please?
<h2>60,47,73</h2>
Step-by-step explanation:
Let the first angle be degrees
Let the second angle be degrees
Let the third angle be degrees
It is given that sum of angles is degrees.
so, ...(i)
It is given that sum of the measures of the second and third angles is two times the measure of the first angle.
...(ii)
It is given that the third angle is 26 more than the second.
...(iii)
using (ii) and (iii),
using (i),(ii) and (iii),
The answer of this is x=0