Answer:
The probability is 
Step-by-step explanation:
We can divide the amount of favourable cases by the total amount of cases.
The total amount of cases is the total amount of ways to put 8 rooks on a chessboard. Since a chessboard has 64 squares, this number is the combinatorial number of 64 with 8,
For a favourable case, you need one rook on each column, and for each column the correspondent rook should be in a diferent row than the rest of the rooks. A favourable case can be represented by a bijective function
with A = {1,2,3,4,5,6,7,8}. f(i) = j represents that the rook located in the column i is located in the row j.
Thus, the total of favourable cases is equal to the total amount of bijective functions between a set of 8 elements. This amount is 8!, because we have 8 possibilities for the first column, 7 for the second one, 6 on the third one, and so on.
We can conclude that the probability for 8 rooks not being able to capture themselves is

3.48 x 10^ -5
move the decimal point back to the first number that isn't zero, if the decimal is moved right 5 spaces, it will be 10^ -5 , if a number has a zero, such as 0.000104, it would be 1.04 x 10^ -4.
Let one side of the square be x
all sides of the square are equal
A=x•x(area formula of a square)
240.25 = x^2
so then the lengths of the sides of the square is 15.5 in
Answer:
D
Step-by-step explanation:
27/12= 2.25
2.25*16=36
Answer:
it's d it makes alot of sense and ik it's right