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guajiro [1.7K]
3 years ago
6

Describe how the graph of g(x) is related to the graph of f(x) = 1/x. g(x) = -1/x +5

Mathematics
1 answer:
umka21 [38]3 years ago
4 0

Answer:

yea

Step-by-step explanation:

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97. An elevator in a tall building goes up 7 floors, then
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so, start floor = x

x + 7 - 9 - 4 + 8 - 2 = 14

x = 14

the elevator started on the 14th floor.

to verify: 14 + 7 = 21 - 9 = 12 - 4 = 8 + 8 = 16 - 2 = 14

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3 years ago
Please, i need help with letter B
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58

Step-by-step explanation:

6*8+2*2+3*2=58

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Eva is working two summer jobs, making $16 per hour tutoring and $8 per hour clearing tables. Last week Eva worked 3 times as ma
DanielleElmas [232]

Answer:

48 and 32 6 hours clearing tables and 2 hours tutoring

Step-by-step explanation:

we can rewrite this as a fraction. we will use 1/10s because 80 can be divided by 8 which is in the problem. we then have to find out what two numbers add up to 8 but one is 3 times the other. 6 and 2 fit into this problem so we plug it into the equation and we write it as this 6x+4x=80 where x is 8. we get 48 and 32.

3 0
2 years ago
The price of a house is originally listed at $205,000. The owners are having a hard time selling it and decide to reduce the pri
VARVARA [1.3K]

Answer:

The percentage decrease is 27%

Step-by-step explanation:

To find the percent decrease, first find the difference in the two costs.

$205,000 - $149,650 = $55,350

Now divide that number by the original cost.

$55,350/$205,000 = 27%

3 0
3 years ago
A second particle, Q, also moves along the x-axis so that its velocity for 0 £ £t 4 is given by Q t cos 0.063 ( ) t 2 v t( ) = 4
Vladimir79 [104]

Answer:

The time interval when V_Q(t) \geq 60  is at  1.866 \leq t \leq 3.519

The distance is 106.109 m

Step-by-step explanation:

The velocity of the second particle Q moving along the x-axis is :

V_{Q}(t)=45\sqrt{t} cos(0.063 \ t^2)

So ; the objective here is to find the time interval and the distance traveled by particle Q during the time interval.

We are also to that :

V_Q(t) \geq 60    between   0 \leq t \leq 4

The schematic free body graphical representation of the above illustration was attached in the file below and the point when V_Q(t) \geq 60  is at 4 is obtained in the parabolic curve.

So, V_Q(t) \geq 60  is at  1.866 \leq t \leq 3.519

Taking the integral of the time interval in order to determine the distance; we have:

distance = \int\limits^{3.519}_{1.866} {V_Q(t)} \, dt

= \int\limits^{3.519}_{1.866} {45\sqrt{t} cos(0.063 \ t^2)} \, dt

= By using the Scientific calculator notation;

distance = 106.109 m

4 0
3 years ago
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