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s2008m [1.1K]
3 years ago
13

1/9 (2m - 16) = 1/3 (2m + 4)

Mathematics
1 answer:
Ainat [17]3 years ago
4 0

Answer:

m=7\frac{5}{16}

Step-by-step explanation:

\frac{1}{9}(2m - 16)=\frac{1}{3}(2m + 4)

\frac{2}{9}m - 1\frac{7}{9} =\frac{2}{3}m+ 1\frac{1}{3}

\frac{2}{9}m - 1\frac{7}{9} -1\frac{1}{3} =\frac{2}{3}m+ 1\frac{1}{3}-1\frac{1}{3}

\frac{2}{9}m - 3\frac{1}{9}  =\frac{2}{3}m

\frac{2}{3}m-\frac{2}{9}m= \frac{2}{9}m -\frac{2}{9}m - 3\frac{1}{9}

\frac{4}{9}m= - 3\frac{1}{9}

\frac{4}{9}m/\frac{4}{9} = - 3\frac{1}{9}/\frac{4}{9}

m=7\frac{5}{16}

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Find k so that the distance from (–1, 1) to (2, k) is 5 units.
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Answer:

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Step-by-step explanation:

The given parameters are;

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\sqrt{\left ((-3)-1 \right )^{2}+\left (2-(-1)  \right )^{2}}= \sqrt{(-4)^2+3^2} = \sqrt{16 + 9}  = \sqrt{25} = 5

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\sqrt{\left (5-1 \right )^{2}+\left (2-(-1)  \right )^{2}}= \sqrt{4^2+3^2} = 5

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