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gizmo_the_mogwai [7]
3 years ago
7

Choose 3 values that would make this inequality true. 7n ≤ 21

Mathematics
1 answer:
vodka [1.7K]3 years ago
7 0

Answer:

A couple could be 2, 1, or even a decimal 1.3 as an example.

Step-by-step explanation:

Divide both sides by 7:

7n/7 < 21/7

n < 3

Any value of n less than 3 will make the inequality true, so just pick three values (numbers) for n that are less than 3, such as n = 2.

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the owner of the store buys calculator for $12. If she marks the up by 30% at what price does she sell them?
worty [1.4K]
Add 12+30% and make sure to add the %
3 0
3 years ago
Read 2 more answers
1. What is the vertex form of the equation?
sergeinik [125]

1.vertex form is y=a(x-h)^2+k

to get into vertex form, complete the square

y=-x^2+12x-4

step 1: group x terms

y=(-x^2+12x)-4

step 2: factor coefient in front of x^2 term

y=-1(x^2-12x)-4

prep for next step: take 1/2 of linear (1st dgree term) and square it

\frac{-12}{2}=-6, (-6)^2=36

step 3: add positive and negative of that previous number inside the parenthasees

y=-1(x^2-12x+36-36)-4

factor perfect squaer trionmial

y=-1((x-6)^2-36)-4

take out that -36 by expansion

y=-1(x-6)^2+36-4

y=-1(x-6)^2+32



2. factor out the 2

2(x^2+8x+12)

what 2 numbers multiply to get 12 and add to get 8?

2 and 6

2(x+2)(x+6)


3.

for ax^2+bx+c=0

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

in our case

x^2-7x-6=0

a=1, b=-7, c=-6

x=\frac{-(-7) \pm \sqrt{(-7)^2-4(1)(-6)}}{2(1)}

x=\frac{7 \pm \sqrt{73}}{2}

so x=\frac{7+\sqrt{73}}{2} and x=\frac{7-\sqrt{73}}{2}



4. remember that i=\sqrt{-1} so i^2=-1

treat i as a variable

(-2i)(8i)=

(-2)(i)(8)(i)=

(-2)(8)(i)(i)=

(-16)(i^2)=

(-16)(-1)=

[tex}16[/tex]

8 0
3 years ago
Read 2 more answers
Plz I need help!! what is 1,2,3????!??????????
STALIN [3.7K]
1: m
2:16
3:6
hoped ihelped 
4 0
4 years ago
Please explain how to solve &amp; the answer!
Levart [38]

Answer:

B

Step-by-step explanation:

given

A = \frac{1}{2}(b_{1} + b_{2})h

multiply both sides by 2 to eliminate the fraction

2A = (b_{1} + b_{2})h

divide both sides by the multiplier h

\frac{2A}{h} = b_{1} + b_{2}

Subtract b_{2} from both sides

\frac{2A}{h} - b_{2} = b_{1}, that is

b_{1} = \frac{2A}{h} - b_{2}

6 0
3 years ago
PLEASE HELP THIS IS DUE TODAY How do you use proportions to calculate missing dimensions in scale drawings?
Rashid [163]

Answer:irst, write the scale factor. Next, write ratios to represent the unknown actual length and width of the display to the scale length and width of the display. Then, write two proportions by setting the two length ratios equal to one another and the two width ratios equal to one another. The given unit is feet

Step-by-step explanation:

4 0
3 years ago
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