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jeyben [28]
3 years ago
12

HIII can some one please HELP ME !!!!

Mathematics
1 answer:
Georgia [21]3 years ago
3 0

Answer:95

Step-by-step explanation:

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Combine the like terms to create a equivalent expression <br> 8r + 7 - 6r -5
Sunny_sXe [5.5K]

Answer:

Step-by-step explanation:

8r - 6r + 7 - 5

2r + 2

8 0
3 years ago
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Find the midpoint of AB if a (-1,7) and B (11,-1)​
Nady [450]

Answer:

  • (5, 3)

Step-by-step explanation:

<h3>Given </h3>
  • Points A(-1,7) and B (11,-1)​
<h3>To find</h3>
  • Midpoint of AB
<h3>Solution</h3>

<u>Using midpoint formula</u>

  • x = (-1 + 11)/2 = 10/2 = 5
  • y = (7 -1)/2 = 6/2 = 3

Midpoint is (5, 3)

8 0
3 years ago
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peter buys 8.5 square feet of carpet. the carpet costs 10.20 per square foot. how much does peter pay for the carpet
sergejj [24]
To get the answer you multiply 8.5 times 10.20 which equals to 86.7
4 0
3 years ago
The vertices of triangle ABC are A(−5, 1), B(−2.5, 7), and C(0, 1). Find the new coordinates of the vertices after the given tra
dybincka [34]

Answer:

<h3>A'(-2,0) , B'(0.5,6) and C'(3,0)</h3>

Step-by-step explanation:

The vertices of triangle ABC are A(−5, 1), B(−2.5, 7), and C(0, 1).

The given translation of vertices,

<h3> (x, y) → (x + 3, y − 1)</h3>

This translation shows shift x-coordinate 3 unit right and y-coordinate 1 unit down.

  • First translate vertices A(-5,1)

A(-5,1)\rightarrow A'(-5+3,1-1)

New vertices A'(-2,0)

  • Now vertices B(-2.5,7)

B(-2.5,7)\rightarrow B'(-2.5+3,7-1)

New vertices B'(0.5,6)

  • Now vertices C(0,1)

C(0,1)\rightarrow C'(0+3,1-1)

New vertices C'(3,0)

Hence, the new coordinate of the vertices are A'(-2,0) , B'(0.5,6) and C'(3,0)

4 0
3 years ago
The correct answer will be marked the brainlest
PtichkaEL [24]

Answer:

8/27

Step-by-step explanation:

(2/3)^3

2^3   3^3

8       27

8/27

5 0
3 years ago
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