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lesya [120]
3 years ago
9

Can someone help me

Mathematics
1 answer:
Hitman42 [59]3 years ago
5 0
Median as there is an outlier (anomaly)
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Given that (5,-8) is on the graph of f(x), find the corresponding point for the function f(x+2)
galben [10]
We know that
the transformation
f(x)--------> f(x+2)
that means
A point (x,y) in graph of f(x)------> become a point (x-2, y) in graph of f(x+2)

hence
point (5,-8)-------------> become a point (5-2,-8)-----> (3,-8)

the answer is
the point (3,-8)
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3 years ago
How many vertices does a triangular prism have? 4 5 6 9
Svetradugi [14.3K]
A triangular prism has 6 vertices. :)
8 0
3 years ago
Read 2 more answers
2y-3[3-4(y-5)+2(1-3y)]
soldi70 [24.7K]

Answer:

- 75 - 32y

Step-by-step explanation:

2y-3[3-4(y-5)+2(1-3y)]

= 2y - 3(3 - 4y + 20 + 2 - 6y)

= 2y - 3(25 - 10y)

= 2y - 75 - 30y

= - 75 - 32y

Brainliest???

4 0
2 years ago
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In the algebraic expression 7/y why is coefficient of y? Explain.
dybincka [34]

Answer:

7 is the (constant) coefficient of 1/y, but no, it is not the coefficient of y

Step-by-step explanation:

7/y can be rewritten as 7(1/y) or as 7(y^[-1]).  In this case, yes, 7 is the (constant) coefficient of 1/y, but no, it is not the coefficient of y.

3 0
3 years ago
A potential energy function is given by U = A x3 + B x2 − C x + D . For positive parameters A, B, C, D this potential has two eq
Ivenika [448]

Answer:

7.8655

Step-by-step explanation:

Given the functionl

U=Ax^3+Bx^2-cx+D

Where,

A=1.45J/m^3\\B=2.85J/m^2\\c= 1.7J/m\\D=0.6J

We have, replacing,

U=1.45x^3+2.85x^2-1.7x+0.6

We need to derivate and verify for stable equilibrum that,

\frac{d^2 U}{dx^2}>0

Then,

U'(x) = 4.32x^2+5.7x-1.7

Roots in,

x_1=-1.57008\\x_2=0.250636

We obtain U"(x), then we have

\frac{d^2U}{dx}=8.64x+5.7

For x=-1.57, U"(x)=-7.86549 Unestable

For x=0.250636 U"(x)=7.8655>0 Stable

7 0
3 years ago
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