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Sati [7]
3 years ago
15

No links/downloads. Please help me with my math homework

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
6 0

Answer:

Step-by-step explanation:

Let's baby-step this to make it easy, ok? Begin by getting rid of all the fractions, which means we will eliminate the 3 from the 1/3 by multiplying both sides be 3:

3V=\pi r^2 h

If we want to eventually isolate the r, we need to move the h and the pi. Do this by division, since each of these is multiplied by r-squared. Doing that gives us:

\frac{3V}{\pi h}=r^2

Lastly, to undo a square, we have to take the square root. We will do that for both sides of the equals sign:

+\sqrt{\frac{3V}{\pi h} }=r

The positive is out front there to indicate that we don't want the negative value since distance is a measure that will never be negative.

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F(x) = 2(x - 3)^2 - 2
Natali5045456 [20]

Hi. I was unsure of what exactly you wanted from this equation, so here's a quick analysis:

<em>f(x) = 2(x - 3)^2 - 2</em>

<em></em>

Domain: (-∞, ∞)

Range: (-2, ∞)

X-intercepts: (4, 0), (2, 0)

Y-intercept: (0, 16)

Axis of Symmetry: x = 3

Minimum value (vertex): (3, -2)

Standard form: y = 2x^2 - 12x + 16

4 0
3 years ago
1/4x + 3/4 = 1/2 ??????????
mart [117]

Answer:

x = -1

Step-by-step explanation:

1/2 = 2/4

____________________________________________________________

1/4x + 3/4 = 2/4

<u>         -3/4     -3/4</u>

1/4x = -1/4

divide by -1/4

x = -1

<em><u>Hope this helped! Have a nice day! Plz mark as brainliest!!!</u></em>

<em><u>-XxDeathshotxX</u></em>

4 0
3 years ago
Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li
krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years

First, let us calculate the decay constant (k)

75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036

Next, let us calculate the half-life as follows:

\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2}  \approx 669\ years

Therefore the half-life is between 600 and 700 years

5 0
3 years ago
An electronics store received two shipments of radios. Of the 250 radios in the first shipment, exactly 6% were damaged. In the
nataly862011 [7]

Answer:

Total number of not damaged = 451

C. 451

Step-by-step explanation:

In the first shipment, 6% of the 250 radios where damaged.

Number of damaged= 6/100 * 250

Number of damaged= 6*2.5

Number of damaged= 15 radios.

Number of not damaged= 250-15

Number of not damaged = 235 radios

In the second shipment, 4% of the radios were damaged

Let the number of second shipment= y

0.04 of y where damaged

Total number of radio damaged= 24

15 + 0.04y = 24

0.04y= 24-15

0.04y = 9

Y= 9/0.04

Y= 225

Number of radio in the second shipment= 225

Number of damaged in the second shipment= 0.04*225

Number of damaged in the second shipment= 9

Number of not damaged in the second shipment= 225-9

Number of damaged in the second shipment= 216

Total number of not damaged

= 235+216

= 451

Total number of not damaged= 451

7 0
3 years ago
A circular pool is 32 foot across.What is the area of the pool rounded to the nearest hundredth of a foot?___square feet.
liberstina [14]

Answer:

correct answer is 95

clear explanation is 86

7 0
2 years ago
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