Is figure B and scale copy of figure A?

Which of the following fractions is not equivalent to 6/21

andreev551 [17]

Answer:

3/7 and 4/14

Step-by-step explanation:

a) 3/7 is not an equivalent of 6/21 because when you multiply the numerator and the denominator by 2 you get: 6/14

b) 4/14 is not an equivalent

4 0

3 years ago

Read 2 more answers

Consider two independent tosses of a fair coin. Let A be the event that the first toss results in heads, let B be the event that

aliina [53]

Answer with Step-by-step explanation:

We are given that two independent tosses of a fair coin.

Sample space={HH,HT,TH,TT}

We have to find that A, B and C are pairwise independent.

According to question

A={HH,HT}

B={HH,TH}

C={TT,HH}

$A\cap B=$ {HH}

$B\cap C$ ={HH}

$A\cap C$ ={HH}

P(E)= $\frac{number\;of\;favorable\;cases}{total\;number\;of\;cases}$

Using the formula

Then, we get

Total number of cases=4

Number of favorable cases to event A=2

$P(A)=\frac{2}{4}=\frac{1}{2}$

Number of favorable cases to event B=2

Number of favorable cases to event C=2

$P(B)=\frac{2}{4}=\frac{1}{2}$

$P(C)=\frac{2}{4}=\frac{1}{2}$

If the two events A and B are independent then

$P(A)\cdot P(B)=P(A\cap B)$

$P(A\cap)=\frac{1}{4}$

$P(B\cap C)=\frac{1}{4}$

$P(A\cap C)=\frac{1}{4}$

$P(A)\cdot P(B)=\frac{1}{2}\cdot \frac{1}{2}=\frac{1}{4}$

$P(B)\cdot P(C)=\frac{1}{4}$

$P(A)\cdot P(C)=\frac{1}{4}$

$P(A)\cdot P(B)=P(A\cap B)$

Therefore, A and B are independent

$P(B)\cdot P(C)=P(B\cap C)$

Therefore, B and C are independent

$P(A\cap C)=P(A)\cdot P(C)$

Therefore, A and C are independent.

Hence, A, B and C are pairwise independent.

6 0

3 years ago

Which of the following statements is true in a one-way ANOVA? a. The critical value of the test will be a value obtained from th

Musya8 [376]

Answer:

d) All of the above

Step-by-step explanation:

A one way analysis of variance (ANOVA) test, is used to test whether there's a significant difference in the mean of 2 or more population or datasets (minimum of 3 in most cases).

In a one way ANOVA the critical value of the test will be a value obtained from the F-distribution.

In a one way ANOVA, if the null hypothesis is rejected, it may still be possible that two or more of the population means are equal.

This one way test is an omnibus test, it only let us know 2 or more group means are statistically different without being specific. Since we mah have 3 or more groups, using post hoc analysis to check, it may still be possible it may still be possible that two or more of the population means are equal.

The degrees of freedom associated with the sum of squares for treatments is equal to one less than the number of populations.

Let's say we are comparing the means of k population. The degree of freedom would be = k - 1

The correct option here is (d).

All of the above

3 0

3 years ago

Find the value of c. 16 = 4 - 3c

dybincka [34]

Answer:

c = -4

Step-by-step explanation:

16 = 4 - 3c

subtract 4 from each side

16-4 = 4-4 - 3c

12 = -3c

Divide each side by -3

12/-3 = -3c/-3

-4 =c

6 0

3 years ago

Read 2 more answers

The radius of the large sphere is double the radius of the

kozerog [31]

Answer:

Given:

Radius of large sphere: R1

Volume of sphere: V1

Radius of small sphere: R2

Volume of sphere: V2

R1=2R2

We know that:

Volume of a sphere: 4/3πR^3

Volume of large sphere: 4/3πR1^3

Now we know that R1=2R2(given)

Thus volume of large sphere(V1) 32/3πR2^3.

Volume of small sphere(V2): 4/3πR2^3.

Ratio of volume of large sphere to small sphere is 8:1.

Step-by-step explanation:

8 0

3 years ago