Y = 3x + b
6 = 3(4) + b
6 = 12 + b, b = -6
Equation: y = 3x - 6
Answer:
B
Step-by-step explanation:
Put the argument value where the variable is, then evaluate.
For f(x), you want f(2).
f(2) = 2² + 1 = 4+1 = 5
For g(x), you want g(1).
g(1) = 3·1 +1 = 4
For [f(2) - g(1)] you want the difference of the above values.
[f(2) - g(1)] = [5 - 4] = 1
Answer:
a = 540°
b= 180°
Step-by-step explanation:
a= pentagon has 5 sides which means 180 × 5= 540
b= 540÷5=180
Let x be the 1st odd number, and x+2 the second odd consecutive number:
(x)(x + 2) = 6[((x) + (x+2)] -1
x² + 2x = 6(2x + 2) - 1
x² + 2x = 12x +12 - 1
And x² - 10x - 11=0
Solve this quadratic expression:
x' = [+10 +√(10²- 4.(1)(-11)]/2 and x" = [+10 -√(10²- 4.(1)(-11)]/2
x' = [10 + √144]/2 and x" = [10 - √64]/2
x' = (10+12)/2 and x" = (10-12)/2
x = 11 and x = -1
We have 2 solutions that satisfy the problem:
1st for x = 11, the numbers at 11 and 13
2nd for x = - 1 , the numbers are -1 and +1
If you plug each one in the original equation :(x)(x + 2) = 6[((x) + (x+2)] -1
you will find that both generates an equlity
