3 years ago

I need help with this math problem please.

Mathematics

1 answer:

9966 [12]3 years ago

8 0

Answer:

b. m/l d.m/3

Step-by-step explanation:

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We must find the common denominator.

LCM(6, 3) = 6

$5\dfrac{1}{6}-1\dfrac{1}{3}=5\dfrac{1}{6}-1\dfrac{1\cdot2}{3\cdot2}=5\dfrac{1}{6}-1\dfrac{2}{6}=(5-1)+\left(\dfrac{1}{6}-\dfrac{2}{6}\right)=4-\dfrac{1}{6}=3\dfrac{5}{6}$

or other method of calculating the difference

$5\dfrac{1}{6}-1\dfrac{2}{6}=4\dfrac{6+1}{6}-1\dfrac{2}{6}=4\dfrac{7}{6}-1\dfrac{2}{6}=(4-1)+\left(\dfrac{7}{6}-\dfrac{2}{6}\right)=3\dfrac{5}{6}$

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A chemist has 10% and 40% solutions of acid available. How many liters of each solution should be mixed to obtain 120 liters of

kaheart [24]

Answer:

100 liters of 10% solution is used and 20 liters of 40% solution is used

Step-by-step explanation:

Let "X" amount of 10% solution is used. Then the amount of 40% solution used is equal to 120-X

Now

10% of X + 40% of (120-X) = 15% of 120

On solving the above equation, we get

$0.1 X + 0.4 (120-X) = 0.15 *120\\0.1 X + 48 -0.4X = 18\\0.3 X = 30\\X = 100$ liters

Amount of 40% solution used = 120 -X = 120-100 = 20 liters

100 liters of 10% solution is used and 20 liters of 40% solution is used

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Step-by-step explanation:

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