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poizon [28]
3 years ago
8

I need help PLEASE!!!!!! I need an answer for the 4th question!!!!

Mathematics
1 answer:
tester [92]3 years ago
3 0

Answer:

The figures from POMN to ZYWX are similar because the scale factor is 1/3 from the biggest shape to the smallest shape. <u>!</u><u> </u><u>T</u><u>H</u><u>I</u><u>S</u><u> </u><u>I</u><u>S</u><u> </u><u>J</u><u>U</u><u>S</u><u>T</u><u> </u><u>A</u><u> </u><u>S</u><u>A</u><u>M</u><u>P</u><u>L</u><u>E</u><u>,</u><u> </u><u>Y</u><u>O</u><u>U</u><u> </u><u>C</u><u>A</u><u>N</u><u> </u><u>W</u><u>R</u><u>I</u><u>T</u><u>E</u><u> </u><u>I</u><u>T</u><u> </u><u>A</u><u>N</u><u>Y</u><u> </u><u>O</u><u>T</u><u>H</u><u>E</u><u>R</u><u> </u><u>W</u><u>A</u><u>Y</u><u>,</u><u> </u><u>I</u><u> </u><u>S</u><u>U</u><u>G</u><u>G</u><u>E</u><u>S</u><u>T</u><u> </u><u>Y</u><u>O</u><u>U</u><u> </u><u>T</u><u>R</u><u>Y</u><u> </u><u>A</u><u>N</u><u>D</u><u> </u><u>M</u><u>A</u><u>K</u><u>E</u><u> </u><u>I</u><u>T</u><u> </u><u>M</u><u>O</u><u>R</u><u>E</u><u> </u><u>I</u><u>M</u><u>P</u><u>R</u><u>O</u><u>V</u><u>E</u><u>D</u><u> </u><u>:</u><u>)</u><u>)</u><u>)</u><u> </u><u>!</u><u> </u>

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Really need help with this pls help!!
worty [1.4K]

Let's carry this math sentence over to its natural, "shapey" element. We're going to look at each term not as an ordinary number, but as <em>the area of some shape</em>.

x² (read as "x <em>squared"</em>) can be seen as the area of a square with side lengths of x. 2x can similarly be seen as the area of a <em>rectangle </em>with a length of x and a width of 2. (Picture 1)

What's our question actually asking, though? Something about <em>perfect squares</em>. More specifically, we're looking for something to add on that'll <em>make this thing a perfect square</em>. We're trying to find a missing piece we can slot in to make a square, in other words. Problem is, our shapes don't look much like a square if we put them together right now. We need to do a little cutting and gluing first.

First, we're gonna cut the 2x rectangle lengthwise, getting two rectangles with an area of x, a length of 1, and a width of x. Next, we're going to attach them to the x² square, creating this shape that looks, strangely, like a square with a little bit missing from it (picture 2). What we're trying to do is <em>complete this square, </em>to find the area of that little missing chunk.

As it turns out, we have all the information we need for this. Notice that, using the lengths of the x rectangles, we can find that the square's dimensions are 1 x 1, which means that its area is 1 x 1  = 1.

If we tack this new area on to our original expression, we've "completed the square!" We now have a perfect square with side lengths of (x + 1) and an area of (x + 1)² (picture 3).

So, our final expression is x² + 2x + 1, and the missing constant - the area of the "missing square" we had to find to complete our larger one - is 1.

5 0
3 years ago
Read 2 more answers
Write the equation of the vertical line that contains (5,-4)
swat32
The answer is y=5x-4
3 0
2 years ago
What if the value of x? show all work
alina1380 [7]
For this case we can make use of the Pythagorean theorem.
 We have then:
 (root (117)) ^ 2 = x ^ 2 + 6 ^ 2
 Clearing x we have:
 x ^ 2 = (root (117)) ^ 2 - 6 ^ 2
 Rewriting:
 x = root (117-36)
 x = root (81)
 x = 9
 Answer:
 
The value of x is given by:
 
x = 9 cm
4 0
3 years ago
PLEASEEE HELPPPP MEE WITH LINE PLOTSSS I DONT UNDERSTAND THISSSS<br> PLEASEE HELPPPP!!!!!!!
Norma-Jean [14]

Answer:

Look at the lightest loaf of bread. It weighs 22 1/3 oz. The heavist loaf weighs 24 1/2. Subtract 24 1/2 and 22 1/3. Then, if the answer to that is 1 1/2 ounces then you agree. If it is not, then disagree. Then, add up all of the weights of the bread and find the answer.

3 0
3 years ago
66 randomly selected students were asked the number of pairs of shoes they have. Let X representthe number of pairs of shoes. Th
laiz [17]

Given data

1. The mean

\frac{\sum fx}{\sum f}=\frac{505}{66}=7.6515

2. The median

\begin{gathered} \text{ Median = (}\frac{\text{N+1}}{2})th \\ =(\frac{66+1}{2})th=(\frac{67}{2})th=33.5th \\ \text{The median is the 33.5th }term\text{ which is between 7 and 8} \\ \text{The median is }\frac{\text{7+8}}{2}=\frac{15}{2}=7.5 \end{gathered}

3. The sample standard deviation

\begin{gathered} SD\text{ =}\sqrt[]{\frac{\sum f|x-\bar{x}|}{\sum f}} \\ \bar{x}=7.6515 \\ SD=\sqrt[]{4.8028} \\ SD=2.1915 \end{gathered}

8 0
1 year ago
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