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2 years ago

11points HELP PLZ!!!

Mathematics

2 answers:

scZoUnD [109]2 years ago

8 0

Answer: 0.00215

Step-by-step explanation:

10^-3 =0.001

2.8 • 0.001 - 0.00065

=0.00215

Mazyrski [523]2 years ago

6 0

Answer:

2.15 × 10⁻³

Step-by-step explanation:

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the

10. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

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PLEASEE HELP ME WITH THIS QUESTION!! Ty

kotykmax [81]

Answer:

Give me a heart and 5 stars

Step-by-step explanation:

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2 years ago

A wire b units long is cut into two pieces. One piece is bent into an equilateral triangle and the other is bent into a circle.

mezya [45]

1. Divide wire b in parts x and b-x.

2. Bend the b-x piece to form a triangle with side (b-x)/3

There are many ways to find the area of the equilateral triangle. One is by the formula A= $\frac{1}{2}sin60^{o}side*side= \frac{1}{2} \frac{ \sqrt{3} }{2} (\frac{b-x}{3}) ^{2}= \frac{ \sqrt{3} }{36}(b-x)^{2}$
A= $\frac{ \sqrt{3} }{36}(b-x)^{2}=\frac{ \sqrt{3} }{36}( b^{2}-2bx+ x^{2} )=\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}$

Another way is apply the formula A=1/2*base*altitude,
where the altitude can be found by applying the pythagorean theorem on the triangle with hypothenuse (b-x)/3 and side (b-x)/6

3. Let x be the circumference of the circle.

$2 \pi r=x$

so $r= \frac{x}{2 \pi }$

Area of circle = $\pi r^{2}= \pi ( \frac{x}{2 \pi } )^{2} = \frac{ \pi }{ 4 \pi ^{2} }* x^{2} = \frac{1}{4 \pi } x^{2}$

4. Let f(x)= $\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}+\frac{1}{4 \pi } x^{2}$

be the function of the sum of the areas of the triangle and circle.

5. f(x) is a minimum means f'(x)=0

f'(x)= $\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x$ =0

$\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x=0$

$(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) x=\frac{ \sqrt{3} }{18}b$

$x= \frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$

6. So one part is $\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$ and the other part is b- $\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$

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3 years ago

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Answer this question if you love Steve being in smash Bros ultimate

lilavasa [31]

Answer:

yes

Step-by-step explanation:

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2 years ago

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Solve for x round to nearest tenth

yawa3891 [41]

Answer:

33.3

Step-by-step explanation:

tan A = opp/adj

tan 39° = 27/x

x tan 39° = 27

x = 27/(tan 39°)

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2 years ago

Find the measure of XCY. PLEASE HELP ME AND SHOW WORK

Dovator [93]

Answer:

Measure of angle XCY is 60°.

Step-by-step explanation:

"Measure of all inscribed angles by the same arc in one segment of the circle are equal"

Using this property in the given circle,

m∠XWY = m∠XCY

60x = 61x - 1

61x - 60x = 1

x = 1

By substituting the value of 'x' in the measure of ∠XCY,

m∠XCY = 61x - 1

= 61(1) - 1

= 61 - 1

= 60°

Therefore, measure of angle XCY is 60°.

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2 years ago