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3 years ago

Solve for b, y = 2x + b

Mathematics

2 answers:

kiruha [24]3 years ago

5 0

Answer:

b= y-2x

Solve for b by simplifying both sides of the equation then isolating the variable.

Vaselesa [24]3 years ago

3 0

Answer:

B = 2x/y - 1 is your answer

Step-by-step explanation:

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Identify the slope, y intercept and x intercept of the graph of the linear equation. y = -3x +9

Alja [10]

Answer:

Slope: -3

Y intercept: (0, 9)

X intercept: (3, 0)

Step-by-step explanation:

In the equation y = mx + b, m is the slope and b is the y intercept.

Since the equation is y = -3x + 9, m is -3 and 9 is the y intercept.

So, the slope is -3 and the y intercept is at (0, 9)

To find the x intercept, plug in 0 as y and solve for x:

y = -3x + 9

0 = -3x + 9

-9 = -3x

3 = x

So, the x intercept is at (3, 0)

6 0

3 years ago

What is 25/22 as a decimal rounded to the nearest hundredth?

Alex777 [14]

Write 35/22 as a decimal How to convert the fraction 35/22 to a decimal value. Please, input values in this format: a b/c or b/c.
<span>
Examples: Four tenths should be typed as 4/10. One and three-half should be typed as 1 3/2. For mixed numbers, please leave a space between the the integer and the fraction.

</span><span>Enter a fraction value:
</span>35/22/ Ex.: 1/2, 2 1/2, 5/3, etc. Note that 2 1/2 means two and half = 2 + 1/2 = 2.5/ Your answer 1.5909090909090908

8 0

3 years ago

In the survey 136 out of 160 depends on modular learning what percent of the reponents prefer modular learning?

xxTIMURxx [149]

C. 85%

Set up the proportions
136/160 = ?/100
Then cross multiply.

100 x 136 = 13600
13600/160 = 85

Also you could use process of elimination. 296% wouldn’t work because that’s saying 136 is almost 3 times as many as 160. The other answers wouldn’t work because it’s clear that 136 is more than half of 160.

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3 years ago

Someone please help me

Bogdan [553]

Ill help you just wait...:)

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4 years ago

Read 2 more answers

How do you simplify this expression with an answer in positive exponential notation? Please provide the process. Thank you!

Otrada [13]

$\bf ~~~~~~~~~~~~\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} \qquad \qquad \cfrac{1}{a^n}\implies a^{-n} \qquad \qquad a^n\implies \cfrac{1}{a^{-n}} \\\\ -------------------------------\\\\ 8^{-2}\cdot \cfrac{3^0-8^{-3}}{4^{-5}}\implies 8^{-2}\cdot \cfrac{1-\frac{1}{8^3}}{\frac{1}{4^5}}\implies 8^{-2}\cdot \cfrac{1-\frac{1}{(2^3)^3}}{\frac{1}{(2^2)^5}}$

$\bf 8^{-2}\cdot \cfrac{\quad \frac{512-1}{2^9}\quad }{\frac{1}{2^{10}}}\implies (2^3)^{-2}\cdot \cfrac{\quad \frac{511}{2^9}\quad }{\frac{1}{2^{10}}}\implies 2^{-6}\cdot \cfrac{511}{2^9}\cdot \cfrac{2^{10}}{1} \\\\\\ 2^{-6}\cdot \cfrac{511\cdot 2^{10}}{2^9}\implies 2^{-6}\cdot 511\cdot 2^{10}\cdot 2^{-9}\implies 2^{-6}\cdot 511\cdot 2^{10-9} \\\\\\ 2^{-6}\cdot 511\cdot 2\implies 511\cdot 2^{-6}\cdot 2\implies 511\cdot 2^{-6+1}\implies 511\cdot 2^{-5} \\\\\\ 511\cdot \cfrac{1}{2^5}\implies \cfrac{511}{32}$

4 0

4 years ago