Can you help me with 1 & 3?

Mathematics

1 answer:

iVinArrow [24]3 years ago

5 0

For 1 multiply both sides by 3 which gives you 3y-y=12. Then combine like terms 2y=12. Lastly divide both sides by 2 and you get y=6. And for 3 first multiply both sides by 4 which gives you 6y-32=y+8. After that combine like terms 6y-y-32=8. Now add the equation together 5y=40 and then divide by 5 and get y=8

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If : f(x)=x^2, g(x)=x-1. Find (f×g)(x).

kramer

Answer:

$\boxed{ f\cdot{g}(x) = x {}^{3} - x {}^{2}}$

Step by step explanation:

Given that,

$f(x) = {x}^{2}$

$g(x) = x - 1$

Solution:

Solving for (f•g)(x):

$= f(x) \cdot g(x)$

Now substitute the given values.

$= x {}^{2} \cdot(x - 1)$

$= x {}^{2} (x - 1)$

Apply distributive property:

$= (x ^{2} \cdot x) - x {}^{2} \cdot 1$

$\boxed{ f\cdot{g}(x) = x {}^{3} - x {}^{2}}$

Hence,f•g(x) will be $x {}^{3} - x {}^{2}$ .

8 0

2 years ago

13 points plus brainliest to the correct answer!

TEA [102]

The equation of a straight line is given by:

y = mx + c

where m is the slope and c is the y-intercept.

From the given graph, the y-intercept is 1.

The slope of a straight line is given by:

$m= \frac{y_2-y_1}{x_2-x_1}$

Where $(x_1,y_1)$ and $(x_2,y_2)$ are two points on the line.

From the graph, (0, 1) and (14, 8) are two points on the line, thus:

$m= \frac{8-1}{14-0} = \frac{7}{14} = \frac{1}{2}$

Therefore, the equation representing the graph is $y= \frac{1}{2} x+1$