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3 years ago

5

Hi what’s 0 divid. Ed bye o9sskwnqzjsmmskmsmskq?

1 answer:

Shtirlitz [24]3 years ago

3 0

Hdjwnwhiw euveidviwvw beiwhebw neneoebe

You might be interested in

It takes 13 more copies of the angle for the last angle to overlap the first horizontal ray. What is the measure of each angle?

nalin [4]

Missing part in the heading of the question:
For this question, use the diagram shown. The diagram shows the result of constructing a copy of an angle adjacent to one of the rays of the original angles. Assume the pattern continues.

Answer:
measure of each angle = 24°

Explanation:
The diagram shows two angles, if we add 13 more copies, the number of angles would be 15 angles

Now, when the 15 angles are drawn, the last angle would overlap with the first horizontal ray.
This means that the angles form one complete rotation around the point.

This means that the sum of the 15 angles together is 360°.

We know the all 15 angles are equal. Assume that the measure of each is x.
15 x = 360
x = 360 / 15
x = 24°

Hope this helps :)

6 0

3 years ago

A track star runs two races on a certain day. The probability thathe wins the first race is 0.7, the probability that he wins th

NARA [144]

Answer:

a) 80% probability that he wins at least one race.

b) 30% probability that he wins exactly one race.

c) 20% probability that he wins neither race.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that he wins the first race.

B is the probability that he wins the second race.

C is the probability that he does not win any of these races.

We have that:

$A = a + (A \cap B)$

In which a is the probability that he wins the first race but not the second and $A \cap B$ is the probability that he wins both these races.

By the same logic, we have that:

$B = b + (A \cap B)$

The probability that he wins both races is 0.5.

This means that $A \cap B = 0.5$

The probability that he wins the second race is 0.6

This means that $B = 0.6$

$B = b + (A \cap B)$

$0.6 = b + 0.5$

$b = 0.1$

The probability that he wins the first race is 0.7.

This means that $A = 0.6$

$A = a + (A \cap B)$

$0.7 = a + 0.5$

$a = 0.2$

A) he wins at least one race.

This is

$P = a + b + (A \cap B) = 0.2 + 0.1 + 0.5 = 0.8$

There is an 80% probability that he wins at least one race.

B) he wins exactly one race.

This is

$P = a + b = 0.2 + 0.1 = 0.3$

There is a 30% probability that he wins exactly one race.

C) he wins neither race

Either he wins at least one race, or he wins neither. The sum of these probabilities is 100%.

From a), we have that there is an 80% probability that he wins at least one race.

So there is a 100-80 = 20% probability that he wins neither race.

6 0

3 years ago

Aleks04 [339]

$\frac{3}{10}$

Answer:

^^

Step-by-step explanation:

I just pressed 27/90 on the calculator hahahha

6 0

2 years ago

Read 2 more answers

Giving brainiest pls help

Rudik [331]

Answer:

Ivan: 4

Caleb: 4, 4, 4, 4, 4, 4, 4

Step-by-step explanation:

For every 4 Ivan sees, Caleb sees 28. (4 times 7)

7 0

2 years ago

The wait time to ride the thunder boats is 30 minutes when 180 people are in line. Write and solve a proportion to find the wait

mars1129 [50]

SO EASY 60 people = 10 minutes in line 240 people = 40 minutes in line

6 0

3 years ago