Exponential growth would include, A = 20,000(1.08)^t, A=40(30), P=1700(1.07).
Decay would include, A=80(1/2)^t, A= 1600(.8), P=1700(.93)
Hope this helps.
Answer:
<h2 /><h2>The interquartile range (IQR) is the difference between the upper (Q3) and lower (Q1) quartiles, and describes the middle 50% of values when ordered from lowest to highest. The IQR is often seen as a better measure of spread than the range as it is not affected by outliers. Interquartile Range. 25% of values.</h2>
<h2 />
<h2>here your answer </h2>
B.) Hibiscus Street
The key thing to remember is the slope of the lines. The equation for a line in slope intercept form is
y = ax + b
where
a = slope
b = y intercept
So the equation for Oak Street is y = 2/3x - 7. So it's slope is 2/3. And any street that has the same slope will be given a tree name. And any street that's perpendicular will be given a flower name. You can determine is a line is perpendicular if it has a slope that's the negative reciprocal. So a street that's perpendicular to Oak street will have a slope of -3/2.
Now you've just been given the equation to a new street that's y = -3/2x - 2. Since the slope is -3/2 and Oak street has a slope of 2/3, the new street is perpendicular to Oak street. And given the naming scheme, that means that the new street will have the name of a flower. So let's look at the available street names and pick a flower.
<span>
A.) Weeping Willow Street
* Nope a Weeping Willow is a tree. So this name won't work.
B.) Hibiscus Street
* Yes. A Hibiscus is a flower, so this name is suitable.
C.) Oak Street
* Nope. Not only is this a tree instead of a flower, but there's already an Oak street. So bad choice.
D.) Panther Street
* Nope, this is an animal, not a flower. Bad choice.
</span>
Answer:
169.04 in² (nearest hundredth)
Step-by-step explanation:
Surface area of a cone = 
r² + r
(where r = radius of the base and = slant height)
Given slant height = 10 and surface area = 188.5
Surface area = r² + r
188.5 = r² + 10r
r² + 10r - 188.5 = 0
r = 
= 4.219621117...
Volume of a cone = (1/3)r²h
(where r = radius of the base and h = height)
We need to find an expression for h in terms of using Pythagoras' Theorem a² + b² = c², where a = radius, b = height and c = slant height
r² + h² = ²
h² = ² - r²
h = √(² - r²)
Therefore, substituting found expression for h:
volume of a cone = (1/3)r²√(² - r²)
Given slant height = 10 and r = 4.219621117...
volume = 169.0431969... = 169.04 in² (nearest hundredth)
The triangle is an isosceles triangle with exactly two congruent angles.
Since the two 45-deg angles are congruent, their opposite sides are also congruent. That makes y = 5.
This triangle is a 45-45-90 triangle. In a 45-45-90 triangle, the legs are congruent and the hypotenuse is sqrt(2) times the length of the legs.
The hypotenuse has length x, so x = 5 * sqrt(2) = 5sqrt(2)
Answer: B. x = 5sqrt(2), y = 5
