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anastassius [24]
2 years ago
11

Logx(x-3)=1 solve for x

Mathematics
1 answer:
faust18 [17]2 years ago
3 0
Answer: x = 0.41092426, 4.5252265
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How do u delete questions lol
max2010maxim [7]

Answer:

i dont think thats possible, sorry ! you can edit them though :)

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Can someone confirm this? is it correct?
EastWind [94]
<span>60 Sorry, but the value of 150 you entered is incorrect. So let's find the correct value. The first thing to do is determine how large the Jefferson High School parking lot was originally. You could do that by adding up the area of 3 regions. They would be a 75x300 ft rectangle, a 75x165 ft rectangle, and a 75x75 ft square. But I'm lazy and another way to calculate that area is take the area of the (300+75)x(165+75) ft square (the sum of the old parking lot plus the area covered by the school) and subtract 300x165 (the area of the school). So (300+75)x(165+75) - 300x165 = 375x240 - 300x165 = 90000 - 49500 = 40500 So the old parking lot covers 40500 square feet. Since we want to double the area, the area that we'll get from the expansion will also be 40500 square feet. So let's setup an equation for that: (375+x)(240+x)-90000 = 40500 The values of 375, 240, and 90000 were gotten from the length and width of the old area covered and one of the intermediate results we calculated when we figured out the area of the old parking lot. Let's expand the equation: (375+x)(240+x)-90000 = 40500 x^2 + 375x + 240x + 90000 - 90000 = 40500 x^2 + 615x = 40500 x^2 + 615x - 40500 = 0 Now we have a normal quadratic equation. Let's use the quadratic formula to find its roots. They are: -675 and 60. Obviously they didn't shrink the area by 675 feet in both dimensions, so we can toss that root out. And the value of 60 makes sense. So the old parking lot was expanded by 60 feet in both dimensions.</span>
8 0
3 years ago
The sum of the squares of two consecutive negative integers is 61. Find the smaller of the two integers
Marysya12 [62]
x^2+(x+1)^2=61\\ x^2+x^2+2x+1-61=0\\ 2x^2+2x-60=0\ \ /:2\\ x^2+x-30=0\\ \Delta=1^2-4\cdot(-40)=1+120=121\ \ \Rightarrow\ \  \sqrt{\Delta} =11\\ \\ x_1= \frac{-1-11}{2} = \frac{-12}{2} =-6,\ \ \ \ x_2= \frac{-1+11}{2} = \frac{10}{2}=5\\ \\Ans.:x=-6
3 0
3 years ago
Write a value-returning recursive function that computes the sum of the digits in a given positive int argument. for example, if
mars1129 [50]
244556
2+4+4+5+5+6=26
5 0
3 years ago
Given: circle k(O), m<br> LM<br> = 164°<br> m<br> WK<br> = 68°, m∠MLK = 65°<br> Find: m∠LMW
Semenov [28]

Let P be a point outside the circle such that triangle LMP has legs coincident with chords MW and LK (i.e. M, W, and P are colinear, and L, K, and P are colinear). By the intersecting secants theorem,

m\angle LPM=\dfrac{m\widehat{LM}-m\widehat{WK}}2\impliesm\angle LPM=48^\circ

The angles in any triangle add to 180 degrees in measure, and \angle MLK\congruent\angle MLP and m\angle LMW=m\angle LMP, so that

m\angle MLK+m\angle LPM+m\angle LMP=180^\circ

\implies\boxed{m\angle LMW=67^\circ}

6 0
3 years ago
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