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3 years ago

PLEASE HELP ASAP THIS WAS DUE YESTERDAY!!!!

Mathematics

1 answer:

Lerok [7]3 years ago

3 0

Answer:

For number 1

Step-by-step explanation:

(3)t. (3)2

3t + 6

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On Wednesday, Mirella hands out flyers to 9 people. On Thursday, each person copies the flyer and hands them out to 9 other peop

3241004551 [841]

Answer:

9 3 (the 9 and 3 are seprete0

Step-by-step explanation:

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3 years ago

a trucker drove 500 miles in h hours. If the trucker averaged 60 mph, which linear equation could be used to find the number of

irina [24]

Step-by-step explanation:

Given that,

Distance covered by a trucker, d = 500 miles

Average speed of the trucker, v = 600 mph

A trucker drove 500 miles in h hours. We need to write the linear equation used to find the number of hours that the trucker drove. Average speed is given by :

$v=\dfrac{d}{t}$

t is time in hours

$t=\dfrac{d}{v}\\\\t=\dfrac{500\ miles}{60\ mph}$

If t is h hours,

$h=\dfrac{500\ miles}{60\ mph}\\\\500=60h$

On solving, h = 5 hours.

Hence, this is the required solution.

5 0

3 years ago

Is it 15, 24, 30, 42, or 48?!

klio [65]

The answer would be

H. 30

Thanks for using Brainly, and Please make sure to make my answer the Brainliest!

6 0

3 years ago

Read 2 more answers

Find the first five terms of the sequence in which a1 = –10 and an = 4an – 1 + 7, if n ≥ 2.

Sholpan [36]

The first five terms of the sequence are -10, -33, -125, -493, -1965

Explanation:

The given expression is $a_n=4a_{n-1}+7$

And $a_1=-10$ is the first term of the sequence.

We need to determine the first five terms of the sequence.

Second term:

Substituting n = 2 in the expression $a_n=4a_{n-1}+7$ , we have,

$a_2=4a_{2-1}+7$

$a_2=4a_1+7$

$a_2=4(-10)+7$

$a_2=-40+7=-33$

Thus, the second term is -33

Third term:

Substituting n = 3 in the expression $a_n=4a_{n-1}+7$ , we have,

$a_3=4a_2+7$

$a_3=4(-33)+7$

$a_3=132+7=-125$

Thus, the third term is -125

Fourth term:

Substituting n = 4 in the expression $a_n=4a_{n-1}+7$ , we have,

$a_4=4a_3+7$

$a_4=4(-125)+7$

$a_4=-500+7=-493$

Thus, the fourth term is -493

Fifth term:

Substituting n = 5 in the expression $a_n=4a_{n-1}+7$ , we have,

$a_5=4a_4+7$

$a_5=4(-493)+7$

$a_5=-1972+7=-1965$

Thus, the fifth term is -1965

Hence, the first five terms of the sequence are -10, -33, -125, -493, -1965

8 0

4 years ago

9x-3y=81. simplified

xxTIMURxx [149]

Answer:

3x-y= 27

Step-by-step explanation:

9x-3y=27

1/3(9x-3y=81)

hence 3x-y=27

3 0

2 years ago