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Kay [80]
3 years ago
10

Tap water is a ______

Mathematics
1 answer:
Anit [1.1K]3 years ago
3 0

Answer:

(running water, city water, town water, municipal water, sink water, etc.) is water supplied to a tap (valve). Its uses include drinking, washing, cooking, and the flushing of toilets. Indoor tap water is distributed through "indoor plumbing", which has existed since antiquity but was available to very few people until the second half of the 19th century when it began to spread in popularity in what are now developed countries. Tap water became common in many regions during the 20th century, and is now lacking mainly among people in poverty, especially on Indian Reservations in the US and in developing countries.

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Example of different types of function.​
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there are many types of functions this includes linear function (straight line graph) eg y=3x+2 , quadratic function (u shaped curve) eg y=x², logarithmic function, exponential function and etc

3 0
3 years ago
What is the Y- intercept of the graph of the line given by equation 3y+4x=15?
KATRIN_1 [288]
Yint is where the line crosses the y axis or where x=0
set x=0

3y+4x=15
x=0
3y+4(0)=15
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yint is (0,5) or at y=5
3 0
3 years ago
The population of a town was 25,000 people. then, 3,200 people moved away.. what was the percent decrease?
bogdanovich [222]
It Is B.21.8%, Simple way to figure this out is round B to 20%, If 3200 equals 20% and 20% times 5 equals 100% all you do is multiply 3200 by 5.
3 0
3 years ago
Read 2 more answers
Water is pumped into a tank at a rate of r (t)=30(1−e− 0.16t) gallons per minute, where t is the number of minutes since the pum
Vlad1618 [11]

Answer:

The total volume of the water in the tank after 20 minutes = 1220 gallons

Step-by-step explanation:

Rate of water pumped into the tank  r (t) = 30 (1 - e^{-0.16 t} )

Initial volume of water in the tank = 800 gallons

The water in the tank after 20 minutes = Initial volume of water in the tank + Volume of water being pumped in the tank

V_{total} = V_{i} + V_{pump}

V_{pump} = \int\limits^a_b {r(t)} \, dt

Where a = 0 , b = 20

Put the value of r (t) in above equation we get

V_{pump} = \int\limits^a_b {30 (1 - e^{-0.16t} )} \, dt

V_{pump} = 30 [ t + \frac{e^{-0.16t} }{0.16} ]

V_{pump} = 30[ (20- 0) + \frac{1}{0.16}(e^{-0.16 (20)}- e^{0}  )

V_{pump} = 420 gallon

Now, total volume in the tank

V_{total} = V_{i} + V_{pump}

V_{total} = 800 + 420

V_{total} = 1220 \ gallon

Therefore the total volume of the water in the tank after 20 minutes = 1220 gallons

3 0
3 years ago
Michael purchased a new office computer system on January 23, 2018, at a cost of $3,791. He does not want to claim bonus depreci
fomenos

Answer:

$3,791

Step-by-step explanation:

$3,791+$3,791-$3,791=3,791 magic!

8 0
3 years ago
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