We know that
volume of a right circular cylinder=pi*r²*h
where
r ----> is the radius
h---> is the height
in this problem
r=6 cm
h=?
Volume=550 cm³
so
V=pi*r²*h------> h=V/[pi*r²]----> h=550/[3.14*6²]----> h=4.87 cm
<span>Round to the nearest tenth
</span>h=4.9 cm
the answer is
4.9 cm
Answer:
its B. y=2(x+7/2)^2+1/2 :)
Step-by-step explanation:
Answer:
B: A square
Step-by-step explanation:
Let's use the process of elimination:
We know that each shape here has opposite parallel sides so there's not much we can do about that one.
All sides congruent automatically gets rid of A.) Rectangle and C.) Parallelogram because they do not <em>always</em> have congruent sides
Opposite angles are congruent gets rid of D.) Rhombus. Although a rhombus can have all congruent angles, it isn't <em>always</em> congruent the way a square is. The definition of a rhombus is a quadrilateral with <em>equal side lengths</em>. Not angles.
So the only shape that meets each criteria all the time is a square.
Answer: Alvin = 42 yrs , Elga = 21 yrs
Step-by-step explanation:
Let Elga's age be x , and Alvin's age be y ,since Alvin is two times Elga's age , then
Alvin's age = 2x , that is
y = 2x ............... equation 1
The sum of their ages is 63 implies
x + y = 63 .............. equation 2
Solving the resulting linear equations by substitution method.
Substitute equation 1 into equation 2 , we have
x + 2x = 63
3x = 63
x = 63/3
x = 21
Therefore : Elga is 21 years old , then Alvin will be 21 x 2, which will be 42
