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yarga [219]
3 years ago
14

A whole number rounded to the nearest ten thousand is 620,000. What is the least possible value for that number?

Mathematics
1 answer:
Ymorist [56]3 years ago
4 0

Answer:

615,000

Step-by-step explanation:

Given that:

Whole number rounded to the nearest ten thousand is 620,000

Let x = the whole number

HTh__ TTh ____ Th ____ H ____ T ____ U

6_____ 2 ______ 0 ____ 0 ____ 0 ____ 0

The ten thousand digit is 0 ;

To round to the nearest 10 thousand, the thousand digit is rounded up to 1 and added to the ten thousand digit if it up to 5 or above and rounded down to 0 if below 5 with all subsequent digits(hundred, tens and unit) rounded to Zero..

Hence,

The whole number will could be range between :

615,000 - 619,999

Hence, the least possible value for the number is 615,000.

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3 years ago
What is the slope of Y=-2/3 X + 2
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6 0
3 years ago
What is the slope of the line?<br> y=-5x-9<br> slope=_______
Lady_Fox [76]
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8 0
3 years ago
Write an equation of the perpendicular bisector of the line segment whose endpoints are (−1,1) and (7,−5)
icang [17]

The equation is y = \frac{3}{2} x - \frac{11}{2}

<u>Explanation:</u>

We have to first find the mid-point of the segment, the formula for which is

(\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2} )

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It is the point at which the segment will be bisected.

Since we are finding a perpendicular bisector, we must determine what slope is perpendicular to that of the existing segment. To determine the segment's slope, we use the slope formula \frac{y_2-y_1}{x_2-x_1}

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To write an equation, substitute the values in y = mx + c

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y = -1

x = 3

m = 3/2

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