Solution for part A is where the red line and the red line meet, (2,-1)
solution for part B: any point on the blue red line is a solution. (2, -1), (0, 3), (3, -3), (-2, 7)
solution for part C is where the green curve and the blue line meet, (0,3)

3 0

3 years ago

Can somebody please give me a step by step explanation. I have the answer I just don’t know how to show work!!!!!!! Please!!!

krek1111 [17]

Answer:

5391.76

Step-by-step explanation:

We have a rectangle and 2 semicircles

First find the area of the rectangle

A = l*w

A = 44*88= 3872

Then we know that 2 semicircles = 1 circle

The area of a circle is

A = pi r^2

The diameter is 44 so the radius is 22

A = pi * 22^2

A = pi484

A =1519.76

Add the areas together

1519.76+3872

5391.76

7 0

3 years ago

Find the values of A B C AND D of <br> 4x^2 (2x^3+5x)= Ax^B +Cx^D

iren2701 [21]

The values are $A=8, B=5, C= 20$ and $D=3$

Explanation:

The expression is $4x^{2} (2x^{3} +5x)=Ax^{B} +Cx^{D}$

Simplifying, we get,

$8x^{5} +20x^3=Ax^{B} +Cx^{D}$

Since, both sides of the expression are equal, we can equate the corresponding values of A, B, C and D.

Thus, we get,

$8 x^{5}=A x^{B}$ ⇒ $A=8$ and $B=5$

Also, equating, $20 x^{3}=C x^{D}$ , we get,

$C=20$ and $D=3$

Thus, the values are $A=8, B=5, C= 20$ and $D=3$

3 0

3 years ago

I don't need you to work it out, just theorem(s) i need to reach the answer :)

VikaD [51]

Not sure why such an old question is showing up on my feed...

Anyway, let $x=\tan^{-1}\dfrac43$ and $y=\sin^{-1}\dfrac35$ . Then we want to find the exact value of $\cos(x-y)$ .

Use the angle difference identity:

$\cos(x-y)=\cos x\cos y+\sin x\sin y$

and right away we find $\sin y=\dfrac35$ . By the Pythagorean theorem, we also find $\cos y=\dfrac45$ . (Actually, this could potentially be negative, but let's assume all angles are in the first quadrant for convenience.)

Meanwhile, if $\tan x=\dfrac43$ , then (by Pythagorean theorem) $\sec x=\dfrac53$ , so $\cos x=\dfrac35$ . And from this, $\sin x=\dfrac45$ .

So,

$\cos\left(\tan^{-1}\dfrac43-\sin^{-1}\dfrac35\right)=\dfrac35\cdot\dfrac45+\dfrac45\cdot\dfrac35=\dfrac{24}{25}$

7 0

3 years ago