Answer:
-38, 62, -100
Step-by-step explanation:
I think you meant a +24, not the -24.
The recursive formula is a_n = a_(n-2) - a_(n-1)
so. we try this 3 times after the -24 term
a_3 = -4 = 2 - 6 = a_1 - a_2
...
a_6 = a_4 - a_5 = 10 - (-14) = 24
a_7 = a_5 - a_6 = -14 - (24) = -38
a_8 = a_6 - a_7 = 24 - (-38) = 62
a_9 = a_7 - a_8 = -38 - 62 = -100
a_10 = a_8 - a_9 = 62 - (-100) = 162
Answer: Adenike scored 64 marks, while Musa scored 45 marks
Step-by-step explanation: We shall start by assigning letters to each unknown variable. Let Adenike’s mark be d while Musa’s mark shall be m.
First of all, if Adenike obtained 19 marks more than Musa, then if Musa scored m, Adenike would score 19 + m (or d = 19 + m). Also if Adenike has obtained one and half her own mark (which would be 1 1/2d or 3d/2), it would have been equal to 6 times more than twice Musa’s mark (or 6 + 2m). This can be expressed as
3d/2 = 6 + 2m. So we now have a pair of simultaneous equations;
d = 19 + m ———(1)
3d/2 = 6 + 2m ———(2)
Substitute for the value of d into equation (2), if d = 19 + m
(3{19 + m})/2 = 6 + 2m
By cross multiplication we now have
3(19 + m) = 2(6 + 2m)
57 + 3m = 12 + 4m
We collect like terms and we have
57 - 12 = 4m - 3m
45 = m
We now substitute for the value of m into equation (1)
d = 19 + m
d = 19 + 45
d = 64
So Adenike scored 64 marks while Musa scored 45 marks
Answer:
There are 12 bottles of water in a full pack.
Step-by-step explanation:
look at screen shot for answer.
All the steps were correct except the final statement. The
mistake was in Line 6.
Line 6 triangle ABC is congruent to triangle EFD by
SAS.
<span>This does not follow. The SAS postulate states
that if two sides and the included angle of one triangle is congruent to two sides
and the included angle of another triangle. The student only proved that one side
of the triangle (AC) is congruent to the side of another triangle (EF) .</span>
Answer: C) n+6
Step-by-step explanation:
You’re increasing so it means you want to add and you must have a serving 6+ and the only one that’s increasing is C
