Answer:
Lower and upper quartiles
Step-by-step explanation:
The box starts at lower quartile, ends at upper quartile
Answer:
y=-2x-1
Step-by-step explanation:
Answer:
![Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779](https://tex.z-dn.net/?f=%20Var%28X%29%20%3D%20E%28X%5E2%29%20-%5BE%28X%29%5D%5E2%20%3D%204.97%20-%281.61%29%5E2%20%3D2.3779)
And the deviation would be:

Step-by-step explanation:
For this case we have the following distribution given:
X 0 1 2 3 4 5 6
P(X) 0.3 0.25 0.2 0.12 0.07 0.04 0.02
For this case we need to find first the expected value given by:

And replacing we got:

Now we can find the second moment given by:

And replacing we got:

And the variance would be given by:
![Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779](https://tex.z-dn.net/?f=%20Var%28X%29%20%3D%20E%28X%5E2%29%20-%5BE%28X%29%5D%5E2%20%3D%204.97%20-%281.61%29%5E2%20%3D2.3779)
And the deviation would be:


To solve for x, we have to remember to isolate the variable.

For 1/2, we can make that 0.5, since their values are equivalent. Our equation:

Let's distribute the 0.5 first.


Now, let's simplify the right side of the equation. We have to distribute the negative to 3x and 1.

Then, we simplify the entire expression.


Our equation now:

Let's add 3x to the right and 3x to the left to simplify the -3x on the right side of the equation.


Let's do the same thing we did in Step 3 to 1.5. Subtract 1.5 on both sides of the equation.


Finally, we divide both sides by 6 to isolate x.

