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Rainbow [258]
2 years ago
5

for an acute angle 0, the equation sin(0) the equation sin(0) = cos(6) is true. What is the value of 0?​

Mathematics
1 answer:
11111nata11111 [884]2 years ago
8 0
The answer for the value of 0 is 0=1
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Find the inverse of the following function.
Naddik [55]

For this case we must find the inverse of the following function:

f (x) = 8 \sqrt {x}

For this, we follow the steps below:

We change f (x) to y:

y = 8 \sqrt {x}

We exchange the variables:

x = 8 \sqrt {y}

We solve for y:

8 \sqrt {y} = x

We divide between 8 on both sides of the equation:

\sqrt {y} = \frac {x} {8}

We raise both sides of the equation to the square to remove the root:

y = (\frac {x} {8}) ^ 2\\y = \frac {x ^ 2} {64}

So, the inverse is:f ^ {- 1} (x) = \frac {x ^ 2} {64}

ANswer:

Option C

3 0
3 years ago
What is the mean of the data set?<br> 17, 24, 26, 13<br> 4<br> 13<br> 20<br> 80
a_sh-v [17]

Answer:

20

Step-by-step explanation:

You need to add all four then divide the answer by 4.

Hope this helps.

6 0
2 years ago
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The area of a rectangular pool is given by the trinomial 2y^2-y-3. What are the possible dimensions of the pool? Use factoring.
RSB [31]

Answer:

(2y−3)(y+1) hope this helps!

7 0
2 years ago
Which graph represents the function f(x)= 1/x - 1<br> PLEASE ANSWER FAST IM TIMED
marusya05 [52]
Number 3, because if you replace x for 1 then you get zero. and because it is rise over run then the run is 0. it is the only line with a run of 0

6 0
3 years ago
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Given: KLMN is a trapezoid m∠N = m∠KML ME ⊥ KN , ME = 3√5 , KE = 8, LM:KN = 3:5 Find: KM, LM, KN, Area of KLMN
lora16 [44]
Q1)Find KM
As ME is perpendicular to KN, ∠KEM is a right angle
Therefore ΔKEM is a right angled triangle 
KE is given and and ME is also given, we need to find KM
for this we can use Pythogoras' theorem where the square of hypotenuse is equal to the sum of the squares of the adjacent sides.
KM² = KE² + ME²
KM² = 8² + (3√5)²
       = 64 + 9x5
KM = √109
KM = 10.44

Q2)Find LM
It is said that ratio of LM:KN is 3:5
Therefore if we take the length of one unit as x
length of LM is 3x
and the length of KN is 5x
KN is greater than LM by 2 units 
If we take the figure ∠K and ∠N are equal. 
Since the angles on opposite sides of the bases are equal then this is called an isosceles trapezoid. So if we draw a line from L that cuts KN perpendicularly at D, ΔKEM and ΔLDN are congruent therefore KE = DN
since KN is greater than LM due to KE and DN , the extra 2 units of KN correspond to 16 units 
KN = LM + 2x 
2x = KE + DN
2x = 8+8
x = 8
LM = 3x = 3*8 = 24

Q3)Find KN 
Since ∠K and ∠N are equal, when we take the 2 triangles KEM and LDN, they both have;
same height ME = LD perpendicular distance between the 2 parallel sides 
same right angle when the perpendicular lines cut KN
∠K = ∠N 
when 2 angles and one side of one triangle is equal to two angles and one side on another triangle then the 2 triangles are congruent according to AAS theorem (AAS). Therefore KE = DN 
the distance ED = LM
Therefore KN = KE + ED + DN
 since ED = LM = 24
and KE + DN = 16
KN = 16 + 24 = 40
another way is since KN = 5x and x = 8
KN = 5 * 8 = 40

Q4)Find area KLMN
Area of trapezium can be calculated using the following general equation 
Area = 1/2 x perpendicular height between parallel lines x (sum of the parallel sides)
where perpendicular height - ME
2 parallel sides are KN and LM
substituting values into the general equation
Area = 1/2 * ME * (KN+ LM) 
         = 1/2 * 3√5 * (40 + 24)
         = 1/2 * 3√5 * 64
         = 3 x 2.23 * 32
         = 214.66 units²


8 0
2 years ago
Read 2 more answers
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