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nadezda [96]
4 years ago
6

How to do this question plz ​

Mathematics
1 answer:
sergeinik [125]4 years ago
3 0

Answer:

The answer is yes.

Step-by-step explanation:

All you have to do is substitute the y, which is 5, and the x, which is 2, into the equation. When you solve it the answer in the end will be 5=5, which means that point (2,5) does line on that line.

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I need some help on this math
olga55 [171]

Answer:

A

Step-by-step explanation:

2n^2/3pq^4-(-3)

7 0
3 years ago
A) Work out (5 x 10^3)x(9 x 10^7)<br> Give your answer in standard form.
Marina86 [1]

Answer:

45000000000

Step-by-step explanation:

when multiplying exponents, you multiply base numbers with no exponent (9 and five in this case) and numbers with exponents (10 in this case). 9 X 5 is 45 and 10 to the power of 7 times 10 to the power of 2 is 10 to the power of 9 or 1000000000. 45 X 1000000000 is 45000000000.

8 0
3 years ago
What are the meaning for those
Tatiana [17]
The mean means average. To find it, add together all of your values and divide by the number of addends. The median is the middle number of your data set when in order from least to greatest. The mode is the number that occurred the most often. The range is the difference between the highest and lowest values.
5 0
3 years ago
The bacterial strain Acinetobacter has been tested for its adhesion properties, which is believed to follow a normal distributio
pantera1 [17]

Answer:

a) Alternative hypothesis should be one sided. Because Null and Alternative hypotheses are:

H_{0}: μ=2.66 dyne-cm.

H_{a}: μ<2.66 dyne-cm.

b) the hypothesis that mean adhesion is at least 2.66 dyne-cm is true

Step-by-step explanation:

Let μ be the mean adhesion in dyne-cm.

a)

Null and alternative hypotheses are:

H_{0}: μ=2.66 dyne-cm.

H_{a}: μ<2.66 dyne-cm.

b)

First we need to calculate test statistic and then the p-value of it.

test statistic of sample mean can be calculated as follows:

t=\frac{X-M}{\frac{s}{\sqrt{N} } } where

  • X  is the sample mean
  • M is the mean adhesion assumed under null hypothesis (2.66 dyne-cm)
  • s is the standard deviation known  (0.7 dyne-cm_2)
  • N is the sample size(5)

Sample mean is the average of 2.69, 5.76, 2.67, 1.62 and 4.12 dyne-cm, that is \frac{2.69+5.76+2.67+1.62+4.12}{5} ≈ 3.37

using the numbers we get

t=\frac{3.37-2.66}{\frac{0.7}{\sqrt{5} } } ≈ 2.27

The p-value is ≈ 0.043. Taking significance level as 0.05, we can conlude that sample proportion is significantly higher than 2.66 dyne-cm.

Thus, according to the sample the hypothesis that mean adhesion is at least 2.66  dyne-cm is true

3 0
4 years ago
use the poisson distribution to find the indicated probability. if the random variable x has a poisson distribution with mean of
Hitman42 [59]
P(X=2)=\frac{e^{-6} 6^{2}}{2}=0.045
4 0
3 years ago
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