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4 years ago

How to do this question plz

Mathematics

1 answer:

sergeinik [125]4 years ago

3 0

Answer:

The answer is yes.

Step-by-step explanation:

All you have to do is substitute the y, which is 5, and the x, which is 2, into the equation. When you solve it the answer in the end will be 5=5, which means that point (2,5) does line on that line.

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945 divided by 35 with remainders

asambeis [7]

Answer:

27.

Step-by-step explanation:

945 / 35 = 27. There are no remainders... Although you could potentially say that 0 is the remainder.

4 0

3 years ago

A car manufacturer estimates that 25% of the new cars sold in one city have defective engine

photoshop1234 [79]

Answer: 672 cars will have defective engine mounds

Step-by-step explanation: 25% of 2,688 is 672

8 0

3 years ago

4y+2/5 -5>3 or 4-3y/6>H

Brums [2.3K]

I think it’s a carrot 100

3 0

3 years ago

What are the zeros of the polynomial function? f(x)=x3+2x2−x−2 Select each correct answer. A.−3 B. −2 C. −1D. 0 E. 1F. 2 G. 3

LenaWriter [7]

Answer:

B. −2

C. −1

E. 1

Step-by-step explanation:

He have been given a polynomial function $f(x)=x^3+2x^2-x-2$ . We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our function with zero and solve for x as:

$x^3+2x^2-x-2=0$

Now, we will factor our equation by grouping method.

$(x^3+2x^2)-(x+2)=0$

$x^2(x+2)-1(x+2)=0$

$(x+2)(x^2-1)=0$

Now, we will use difference of squares $a^b-b^2=(a+b)(a-b)$

$(x+2)(x^2-1^2)=0$

$(x+2)(x+1)(x-1)=0$

Using zero product property, we will get:

$(x+2)=0\text{ or }(x+1)=0\text{ or }(x-1)=0$

$x=-2\text{ or }x=-1\text{ or }x=1$

Since the zeros of our given function are $-2,-1\text{ and }1$ , therefore, options B, C and E are correct choices.

4 0

3 years ago

Find the result when 5m+2 is subtracted from 9m

Shkiper50 [21]

Answer:

Step-by-step explanation:

9m - (5m-2) =

5m-2= 3m

9m - 3m= 6m

Please give Brainliest if it helped.

5 0

3 years ago

How to do this question plz ​

How to do this question plz