3 years ago

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SAT

1 answer:

Annette [7]3 years ago

4 0

Answer:

Group 15

Explanation:

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A child riding a bicycle at 15 m/s accelerates at 3. 0 m/s/s for 4. 0 s. What is the child's speed at the end of this 4. 0 s int

mamaluj [8]

Answer:

The final speed of bicycle would be 27 m/s².

Step-by-step explanation:

Given :

$\small\red\bull$ Initial velocity (u) = 15 m/s
$\small\red\bull$ Acceleration (a) = 3.0 m/s²
$\small\red\bull$ Time = 4 seconds

To Find :

$\small\red\bull$ Final velocity (v)

Using Formula :

$\longrightarrow{\pmb{\sf{v = u + at}}}$

$\small\blue\star$ v = final velocity
$\small\blue\star$ u = initial velocity
$\small\blue\star$ a = acceleration
$\small\blue\star$ t = time taken

Solution :

Substituting the values in the formula to find the final velocity :

$\longrightarrow{\sf{v = u + at}}$

$\longrightarrow{\sf{v = 15 + (3.0 \times 4)}}$

$\longrightarrow{\sf{v = 15 + (3 \times 4)}}$

$\longrightarrow{\sf{v = 15 +(12)}}$

$\longrightarrow{\sf{v = 15 +12}}$

$\longrightarrow{\sf{v = 27 \: {m/s}^{2}}}$

$\star{\underline{\boxed{\red{\sf{v = 27 \: {m/s}^{2}}}}}}$

Hence, the final speed of bicycle would be 27 m/s².

$\rule{300}{1.5}$

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