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2 years ago

Https://docs.go.ogle.com/document/d/18Hdsr_QPHUmxQcSeVTpAPhbCisMVVB2G3gtipEc_fGA/edit?usp=sharing

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1 answer:

alexandr402 [8]2 years ago

5 0

Answer:

2. ( Image is attached down at the bottom! Its the redish pinkish one with purple. )

17. ( The image is also down below which is the black and white and gray one )

27. ( Image is down below which is the gray, blue, red, orange, black and purple one )

Explanation:

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How many grams of sucrose, c12h22o11, must be added to 500. G of water at 100°c to change the vapor pressure to 752 mm hg?.

denpristay [2]

The mass number of sucrose that must be added to 500 g of water is 100.979 grams

To be able to solve this question, we need to use the number of moles concept and mole fraction concept.

<h3>What is the number of moles?</h3>

The number of moles is related to the mass of the substance divided by the molar mass of the substance.

From the given parameters;

The number of moles of water = mass/molar mass

Mass of water = 500 g
the molar mass of water = 18.02 g/mol

number of moles = 500 g/ 18.02 g/mol

number of moles = 27.75 moles

However,

the standard vapor pressure of the solvent $\mathbf{P^0_{water}}$ = 760 mmHg

the vapor pressure of the solute = 752 mmHg

Using the mole concept:

$\mathbf {X_{C_{12}H_{22}O_{11}} = \dfrac{n_{C_{12}H_{22}O_{11}}}{n_{H_2O}+n_{C_{12}H_{22}O_{11}}} }$

By relative lowering of vapor pressure:

$\mathbf{\dfrac{P^0_{H_2O} - P_{H_2O}}{P^0_{H_2O}} = X_{C_{12}H_{22}O_{11}}}$

$\mathbf{\dfrac{760 -752}{760} = \dfrac{n_{C_{12}H_{22}O_{11}}}{27.75 +n_{C_{12}H_{22}O_{11}}} }}$

$\mathbf{0.01053 = \dfrac{n_{C_{12}H_{22}O_{11}}}{27.75 +n_{C_{12}H_{22}O_{11}}} }}$

$\\ \\ \mathbf{0.01053 (27.75) +0.01053 (n_{C_{12}H_{22}O_{11}} ) = n_{C_{12}H_{22}O_{11}}}$

$\\ \\ \mathbf{0.2922075 =0.98947
 (n_{C_{12}H_{22}O_{11}} )}$

$\\ \\ \mathbf{ (n_{C_{12}H_{22}O_{11}} ) = \dfrac{0.2922075 }{0.98947}}$

$\\ \\ \mathbf{ (n_{C_{12}H_{22}O_{11}} ) =0.295 \ moles}$

The mass of sucrose = number of moles × molar mass

The mass of sucrose = 0.295 moles × 342.3 g/mol

The mass of sucrose = 100.979 grams

Learn more about number of moles here:

brainly.com/question/13314627

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