Answer:
location is in centre
charge is positive
mass is 99 percent mass of an atom
Answer:
the chemical in the same group or table
The concentration of Iron in the galvanic (voltaic) cell Fe(s) + Mn²⁺(aq) ⟶ Fe²⁺(aq) + Mn(s) is 0.02297 M.
<h3>What is the Nernst Equation?</h3>
The Nernst equation enables us to identify the cell potential(voltage) in presence of non-standard conditions in a galvanic cell. It can be expressed by using the formula:
![\mathbf{E_{cell} = E_o - \dfrac{0.059}{n} \times log \dfrac{[Fe^+]}{[Mn^{2+}]}}](https://tex.z-dn.net/?f=%5Cmathbf%7BE_%7Bcell%7D%20%3D%20E_o%20-%20%5Cdfrac%7B0.059%7D%7Bn%7D%20%5Ctimes%20log%20%5Cdfrac%7B%5BFe%5E%2B%5D%7D%7B%5BMn%5E%7B2%2B%7D%5D%7D%7D)
where;
- n = Number of electrons = 2
= Initial voltage = 0.77 V
= Cell voltage = 0.78 V![\mathbf{[Mn^{2+}]}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5BMn%5E%7B2%2B%7D%5D%7D)
= Manganese concentration = 0.050 M
Replacing the values into the above equation, we have:
![\mathbf{0.78 = 0.77 - \dfrac{0.059}{2} \times log \dfrac{[Fe^{2+}]}{[0.050]}}](https://tex.z-dn.net/?f=%5Cmathbf%7B0.78%20%3D%200.77%20-%20%5Cdfrac%7B0.059%7D%7B2%7D%20%5Ctimes%20log%20%5Cdfrac%7B%5BFe%5E%7B2%2B%7D%5D%7D%7B%5B0.050%5D%7D%7D)
![\mathbf{0.78 -0.77= -0.0296\times log \dfrac{[Fe^{2+}]}{[0.050]}}](https://tex.z-dn.net/?f=%5Cmathbf%7B0.78%20-0.77%3D%20-0.0296%5Ctimes%20log%20%5Cdfrac%7B%5BFe%5E%7B2%2B%7D%5D%7D%7B%5B0.050%5D%7D%7D)
![\mathbf{log^{-1} (-0.3378) = \dfrac{[Fe^{2+}]}{[0.050]}}](https://tex.z-dn.net/?f=%5Cmathbf%7Blog%5E%7B-1%7D%20%28-0.3378%29%20%3D%20%5Cdfrac%7B%5BFe%5E%7B2%2B%7D%5D%7D%7B%5B0.050%5D%7D%7D)
Learn more about using the Nernst equation here:
brainly.com/question/24258023
Answer:
B. CH₅N
Explanation:
The combustion reaction of a compound CₐHₓNₙ with O₂ is:
CₐHₓNₙ + O₂ → a CO₂ + X/2 H₂O + n NO₂
Where 1 mole of CₐHₓNₙ with an excess of O₂ produce a moles of CO₂, X/2 moles of H₂O and n moles of NO₂
Thus, you need to convert the mass of CO₂ and H₂O to moles to find the C:H ratio and determine a possible empirical formula thus:
Moles CO₂ (Molar mass 44g/mol):
44g ₓ (1mol / 44g) = 1 mole CO₂ = 1 mole C
Mole of H₂O (Molar mass 18g/mol):
45g ₓ (1 mol / 18g) = 2.5 moles H₂O = 5 moles H
Thus, in the compound you have 5 moles of H per mole of C, and a possible empirical formula is:
B. CH₅N
The only structure that meet this C:H ratio
