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Afina-wow [57]
3 years ago
15

A local high school held a two-day fundraiser selling lunches. The equations shown represent the amount of money the school coll

ected during the two days. {12x + 4y = 15232x + 12y = 420 In the equations, x represents the cost of a chicken lunch and y represents the cost of a vegetarian lunch. Which is the cost of the vegetarian lunch?
Mathematics
1 answer:
kramer3 years ago
8 0

Answer:

  11

Step-by-step explanation:

The two equations appear to be ...

  • 12x +4y = 152
  • 32x +12y = 420

These can be solved for y using Cramer's rule:

  y = (152(32) -420(12))/(4(32) -12(12)) = -176/-16 = 11

The cost of the vegetarian lunch is 11.

_____

<em>Comment on Cramer's Rule</em>

For equations ...

  ax +by =c

  dx +ey = f

The solutions are ...

  x = (bf -ey)/(bd -ea)

  y = (cd -fa)/(bd -ea) . . . . note the denominators are the same expression

Once you memorize the pattern of products, this can be the simplest way to solve a pair of equations--especially if you only need one of the variable values.

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Which of the following are solutions to the equation below?
scoundrel [369]

Answer:

The correct options for the solution values are:

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  • x=-2\sqrt{2}-5

Step-by-step explanation:

Given the expression

x^2+10x+25=8

Subtract 25 from both sides

x^2+10x+25-25=8-25

Simplify

x^2+10x=-17

Add 25 or 5² to both sides

x^2+10x+5^2=8

as

x^2+10x+5^2=\left(x+5\right)^2

so the expression becomes

\left(x+5\right)^2=8

\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}

solve

x+5=\sqrt{8}

Subtract 5 from both sides

x+5-5=2\sqrt{2}-5

x=2\sqrt{2}-5

solve

x+5=-\sqrt{8}

Subtract 5 from both sides

x+5-5=-2\sqrt{2}-5

x=-2\sqrt{2}-5

Therefore, the solution to the equation

x=2\sqrt{2}-5,\:x=-2\sqrt{2}-5

Hence, the correct options for the solution values are:

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  • x=-2\sqrt{2}-5

6 0
3 years ago
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