X - 4y = 2.....multiply by -3
3x + 2y = 6
-------------
-3x + 12y = -6 (result of multiplying by -3)
3x + 2y = 6
------------add
14y = 0
y = 0
3x + 2y = 6
3x + 2(0) = 6
3x = 6
x = 6/3
x = 2
solution is (2,0).....so the graph that has the two lines intersecting (crossing) at (2,0) is gonna be ur graph
Answer:
1, x = 80
2, z = 5.6
3, w = 18
Step-by-step explanation:
<span>280
I'm assuming that this question is badly formatted and that the actual number of appetizers is 7, the number of entres is 10, and that there's 4 choices of desserts. So let's take each course by itself.
You can choose 1 of 7 appetizers. So we have
n = 7
After that, you chose an entre, so the number of possible meals to this point is
n = 7 * 10 = 70
Finally, you finish off with a dessert, so the number of meals is:
n = 70 * 4 = 280
Therefore the number of possible meals you can have is 280.
Note: If the values of 77, 1010 and 44 aren't errors, but are actually correct, then the number of meals is
n = 77 * 1010 * 44 = 3421880
But I believe that it's highly unlikely that the numbers in this problem are correct. Just imagine the amount of time it would take for someone to read a menu with over a thousand entres in it. And working in that kitchen would be an absolute nightmare.</span>
Answer:
D is the correct answer
Step-by-step explanation:
I just took the test
