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3 years ago

Please I really need help

Mathematics

2 answers:

tiny-mole [99]3 years ago

4 0

$60
hope this helps! (if I’m wrong I apologize.)

svet-max [94.6K]3 years ago

3 0

Answer:

I dont know byeeeeeee

Step-by-step explanation:

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A boat traveled 153 miles downstream and back. The trip downstream took 9 hours. The trip back took 17 hours. What is the speed

fgiga [73]

Speed of boat in still water is 13 miles per hour and speed of current is 4 miles per hour

<h3><u><em>Solution:</em></u></h3>

Let s = the speed of the boat in still water in miles/hour

Let c = the speed of the current in miles/hour

<em><u>Formula to remember:</u></em>

If the speed of a boat in still water is s miles/hr and the speed of the current is c miles/hr, then:

Speed downstream = (s + c) miles per hour

Speed upstream = (s - c) miles per hour

<em><u>Given:</u></em>

boat traveled 153 miles downstream and back

distance for downstream = 153 miles

distance for upstream = 153 miles

time taken for downstream = 9 hours

Time taken for upstream = 17 hours

<em><u>The relation between speed, distance and time is given as:</u></em>

$distance = speed \times time$

<em><u>For downstream:</u></em>

$153 = (s + c) \times 9$

$s + c = \frac{153}{9} = 17$

s + c = 17 ------- eqn 1

<em><u>For upstream:</u></em>

$153 = (s - c) \times 17\\\\s - c = \frac{153}{17} = 9$

s - c = 9 ------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to find values of "s" and "c"</u></em>

Add eqn 1 and eqn 2

s + c = 17

s - c = 9

(+) -------------

2s = 26

Substitute s = 13 in eqn 1

13 + c = 17

c = 17 - 13 = 4

Thus the speed of boat in still water is 13 miles per hour and speed of current is 4 miles per hour

8 0

3 years ago

What is the area of rhombus ABCD? Enter your answer in the box. Do not round at any steps. put the answer in units²

AlladinOne [14]

Answer:

Therefore the Area of Rhombus ABCD is 36 unit².

Step-by-step explanation:

Given:

ABCD is a Rhombus

A = (-1,0)

B = (5,-3)

C = (-1,-6)

D = (-7 ,-3)

To Find:

Area of Rhombus ABCD = ?

Solution:

We know that Area of Rhombus is given as

$\textrm{Area of Rhombus}=\dfrac{1}{2}\times d_{1}\times d_{2}$

Where ,

d₁ and d₂ are the Diagonals.

We have,

Diagonals as AC and BD,

Using Distance Formula we get

$l(AC) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}$

Substituting coordinates A and C we get

$l(AC) = \sqrt{((-1-(-1))^{2}+(-6-0)^{2} )}=\sqrt{36}\\l(AC)=6\ unit$

Similarly for BD we have,

$l(BD) = \sqrt{((5-(-7))^{2}+(-3-(-3))^{2} )}=\sqrt{144}\\l(BD)=12\ unit$

Now Substituting AC and BD in Formula we get

$\textrm{Area of Rhombus}=\dfrac{1}{2}\times AC\times BD$

$\textrm{Area of Rhombus}=\dfrac{1}{2}\times 6\times 12=36\ unit^{2}$

Therefore the Area of Rhombus ABCD is 36 unit².

6 0

3 years ago

Is 6/11 greater than 9/14

4vir4ik [10]

No because when you cross multiply 9/24 has a bigger number

3 0

4 years ago

What is the ratio of 30 to 66 in simplest form

Lena [83]

5.11!!!!! -Skyler Scar.

6 0

3 years ago

By converting 3pt/2 from radians to degrees, the answer will be

zubka84 [21]

Answer:

Step-by-step explanation:

To convert radians to degrees

degree = radian × $\frac{180}{\pi }$ , then

$\frac{3\pi }{2}$ × $\frac{180}{\pi }$ ( cancel π on numerator/ denominator )

= $\frac{3(180)}{2}$

= $\frac{540}{2}$

= 270° → C

3 0

2 years ago

Please I really need help​

Please I really need help