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goldfiish [28.3K]
3 years ago
5

Please help me fast please

Mathematics
1 answer:
stiks02 [169]3 years ago
5 0

Answer:

11

Step-by-step explanation:

Angle OKL is also angle 12. The only angle number that is adjacent, or shares a side with 12 is angle 11.

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3 years ago
Please help!!! Use the Pythagorean theorem to find the missing value
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Answer: 1. is 50 2. is 111  3. is 26 4. is 45  and 5. is 51

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3 years ago
Find all points on the x-axis that are 14 units from the point (4, -7).
BaLLatris [955]

Answer:

The points are: (16.12,0),(-8.12,0).

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

Distance between two points:

Suppose we have two points, (x_1,y_1) and (x_2,y_2). The distance between them is given by:

D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Find all points on the x-axis that are 14 units from the point (4, -7).

Being on the x-axis mean that they have y-coordinate equal to 0, so the point is (x,0).

The distance is 14. So

\sqrt{(x-4)^2+(0-(-7))^2} = 14

\sqrt{x^2 - 8x + 16 + 49} = 14

\sqrt{x^2 - 8x + 65} = 14

(\sqrt{x^2 - 8x + 65})^2 = 14^2

x^2 - 8x + 65 - 196 = 0

x^2 - 8x - 131 = 0

So a = 1, b = -8, c = -131

\bigtriangleup = (-8)^{2} - 4(1)(-131) = 588

x_{1} = \frac{-(-8) + \sqrt{588}}{2} = 16.12

x_{1} = \frac{-(-8) - \sqrt{588}}{2} = -8.12

The points are: (16.12,0),(-8.12,0).

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