5 is common factor
also x
reverse distributive
ab+ac=a(b+c)
5x(x)+5x(4)=5x(x+4)
last one
<span>Carl has 3 bags in total. One backpack weighs 4 kg and the rest two checking bags have the equal weight. The total weight of 3 bags is given to be 35 kg.
Let the weight of each checking bag is w kg. So we can write:
2 x (Weight of a checking bag) + Weight of Backpack = 35
Using the values, we get:
2w+ 4 = 35
Using this equation we can find the weight of each checking bag, as shown below.
2w = 31
w = 31/2
w = 15.5
Thus, the weight of each checking bag is 15.5 kg
</span>
3(x-9)
when you distribute the equation you get
3(x)-3(9) which is the last answer
The answer is y=2. Hope this helps!
