Answer:
14
Step-by-step explanation:
7 × 2 = 14
the number you thought of was 14
:)
Hi There!
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Question #1:
Total Cost for Kites-R-Fun: y = 8x + 0
Total Cost for Windy Kites: y = 20x + 0
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Question #2:
![\left[\begin{array}{ccc}Kites-R-Fun&Windy Kites\\8&20\\16&40\\24&60\\32&80\\40&100\\48&120\\56&140\\64&160\\72&180\\80&200\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7DKites-R-Fun%26Windy%20Kites%5C%5C8%2620%5C%5C16%2640%5C%5C24%2660%5C%5C32%2680%5C%5C40%26100%5C%5C48%26120%5C%5C56%26140%5C%5C64%26160%5C%5C72%26180%5C%5C80%26200%5Cend%7Barray%7D%5Cright%5D)
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Hope This Helps :)
If
(2 sin(x) - 1) (2 cos²(x) - 1) = 0
then either
2 sin(x) - 1 = 0 or 2 cos²(x) - 1 = 0
sin(x) = 1/2 or cos(2x) = 0
The first equation gives two families of solutions,
x = arcsin(1/2) + 2nπ = π/6 + 2nπ
x = π - arcsin(1/2) + 2nπ = 5π/6 + 2nπ
where n is any integer; we get the solutions x = π/6 and x = 5π/6 in the interval 0 ≤ x < 2π when n = 0.
The second equation also gives two families of solutions,
2x = arccos(0) + 2nπ = π/2 + 2nπ
2x = -arccos(0) + 2nπ = -π/2 + 2nπ
Divide both sides by 2 :
x = π/4 + nπ
x = -π/4 + nπ
Then the solutions we want are x = π/4 and x = 5π/4 (when n = 0 and 1 in the first family, respectively) and x = 3π/4 and x = 7π/4 (when n = 1 and 2 in the second family).
We have 6 solutions, so A is the correct choice.
Answer:
The 2nd and last one
Step-by-step explanation:
Answer: D it makes the most since as both numerators are equal to each other and the denominators will have to be the same for them to be equal.
Step-by-step explanation:
