The number of shoppers per day would be 192 and the number of shoppers per hour would be 24. hope this helps
Answer:
Dh/dt = 0.082 ft/min
Step-by-step explanation:
As a perpendicular cross section of the trough is in the shape of an isosceles triangle the trough has a circular cone shape wit base of 1 feet and height h = 2 feet.
The volume of a circular cone is:
V(c) = 1/3 * π*r²*h
Then differentiating on both sides of the equation we get:
DV(c)/dt = 1/3* π*r² * Dh/dt (1)
We know that DV(c) / dt is 1 ft³ / 5 min or 1/5 ft³/min
and we are were asked how fast is the water rising when the water is 1/2 foot deep. We need to know what is the value of r at that moment
By proportion we know
r/h ( at the top of the cone 0,5/ 2) is equal to r/0.5 when water is 1/2 foot deep
Then r/h = 0,5/2 = r/0.5
r = (0,5)*( 0.5) / 2 ⇒ r = 0,125 ft
Then in equation (1) we got
(1/5) / 1/3* π*r² = Dh/dt
Dh/dt = 1/ 5*0.01635
Dh/dt = 0.082 ft/min
Answer:
There are two answers, either of which would work
- 26°, 26° and 128°
- 26°, 77° and 77°
Method:
An isosceles triangle has 2 of the same sides so there are two possible answers:
1) 26° is one of the angles which is the same as another. 26° × 2 = 52° and since there are 180° in a triangle the other angle is 180° - 52° which is 128°. This would make the angles 26°, 26° and 128°
2) 26° is not one of the angles which is the same as another. Since there are 180° in a triangle, the other angles would both be 2 ÷ (180° - 26°) which is 77°. This would make the angless 26°, 77° and 77°
Answer:
90
Step-by-step explanation:
Answer:
uhh i think
Step-by-step explanation:
just the horizontal and the diagonal
can i have brainliest plz
