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3 years ago

Which of the following coordinate points have an x-value of 4? Select all that apply.

Mathematics

2 answers:

Alinara [238K]3 years ago

7 0

B, C, and D all have an x-value of 4.

kodGreya [7K]3 years ago

7 0

Answer:

it b

Step-by-step explanation:

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I need help on understanding this concept

Sedbober [7]

So the slope formula is m= (y2-y1) /
(x2-x1). You can label -2 as x1 and 11 as y1. And the other point is x2 and y2. They you just plug it in the m= (y2-y1) /
(x2-x1) formula and solve. To get a better understanding look up, how to find the slope of a line with two points. Hope it helps

3 0

3 years ago

Can anyone do this with steps ..

Harrizon [31]

$\\ \sf\longmapsto \displaystyle{\lim_{x\to 0}}\dfrac{sinx-sin3x}{sins3x-sinx}$

$\boxed{\sf \displaystyle\lim_{x\to 0}\dfrac{f(x)}{g(x)}=\dfrac{\lim_{x\to 0}f(x)}{\lim_{x\to 0}g(x)}}$

Now

$\\ \sf\longmapsto \displaystyle{\dfrac{\lim_{x\to 0}sinx-\lim_{x\to 0}sin3x}{\lim_{x\to 0}sin3x-\lim_{x\to 0}sinx}}$

$\boxed{\sf \displaystyle{\lim_{x\to 0}}f(x)=f(a)}$

$\\ \sf\longmapsto \dfrac{sin0-sin3(0)}{sin3(0)-sin0}$

$\\ \sf\longmapsto \dfrac{0-0}{0-0}$

$\\ \sf\longmapsto \dfrac{0}{0}$

$\\ \sf\longmapsto 0$

7 0

3 years ago

A city averages 14 hours of daylight in June (the longest days) and 10 in December (the shortest days). Assume that the number o

UNO [17]

The equation is given as

$y = 12 sin (6t - \pi /2) + 2$

<h3>The Amplitude </h3>

The Amplitude can be calculated as

$amplitude = \frac{max + min}{2}\\ amplitude = \frac{10+14}{2} = 12$

<h3>The Vertical Shift</h3>

The vertical shift is the average difference between the maximum and minimum.

$Vertical Shift = \frac{Max - Min}{2} = \frac{14-10}{2} = 2$

For b value

The Time Period will be twice the distance between max and min.

$time period = \frac{2\pi }{b} \\time period = 2 * distance between max and min\\b = \frac{2\pi }{2}*\frac{1}{b} = \frac{\pi }{6}$

<h3>The Period</h3>

The period is calculated as

$T = \frac{2\pi }{b} \\T = \frac{2\pi }{\frac{\pi }{b} } = 12$

The equation is given as

$y = 12 sin (6t - \pi /2) + 2$

Learn more on time period and amplitude here;

brainly.com/question/15531840

8 0

2 years ago

Elena went 60 meters in 50 seconds. Noah went 50 meters in 10 seconds. Elena and Noah both moved at a constant speed. Who went f

photoshop1234 [79]

Noah because he went way faster

6 0

3 years ago

A quality-conscious disk manufacturer wishes to know the fraction of disks his company makes which are defective. Step 2 of 2 :

const2013 [10]

Answer:

The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

Suppose a sample of 1067 floppy disks is drawn. Of these disks, 74 were defective.

This means that $n = 1067, \pi = \frac{74}{1067} = 0.069$

80% confidence level

So $\alpha = 0.2$ , z is the value of Z that has a pvalue of $1 - \frac{0.2}{2} = 0.9$ , so $Z = 1.28$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.069 - 1.28\sqrt{\frac{0.069*0.931}{1067}} = 0.059$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.069 + 1.28\sqrt{\frac{0.069*0.931}{1067}} = 0.079$

The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).

7 0

3 years ago