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bogdanovich [222]
3 years ago
9

Can anyone do this with steps ..

Mathematics
1 answer:
Harrizon [31]3 years ago
7 0

\\ \sf\longmapsto \displaystyle{\lim_{x\to 0}}\dfrac{sinx-sin3x}{sins3x-sinx}

\boxed{\sf \displaystyle\lim_{x\to 0}\dfrac{f(x)}{g(x)}=\dfrac{\lim_{x\to 0}f(x)}{\lim_{x\to 0}g(x)}}

Now

\\ \sf\longmapsto \displaystyle{\dfrac{\lim_{x\to 0}sinx-\lim_{x\to 0}sin3x}{\lim_{x\to 0}sin3x-\lim_{x\to 0}sinx}}

\boxed{\sf \displaystyle{\lim_{x\to 0}}f(x)=f(a)}

\\ \sf\longmapsto \dfrac{sin0-sin3(0)}{sin3(0)-sin0}

\\ \sf\longmapsto \dfrac{0-0}{0-0}

\\ \sf\longmapsto \dfrac{0}{0}

\\ \sf\longmapsto 0

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