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Tatiana [17]
3 years ago
12

Calculate 3(8-6)

absmiddle" class="latex-formula">
​
Mathematics
2 answers:
svlad2 [7]3 years ago
4 0

Answer:

6

Step-by-step explanation:

3(8−6)

=(3)(2)

=6

irakobra [83]3 years ago
3 0

Answer:

3(8-6)=6

Step-by-step explanation:

8-6

=2

=3*2

=6

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strojnjashka [21]

We don't really have to put this in slope intercept form; it would clearly end up as

y = -4x + something

so we know the slope is -4.

Answer:  C)   -4

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Can someone please explain to me how to solve this problem?
Svetradugi [14.3K]
Bro that is so easy!!
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Write 3 tens 9 ones in another way
Vsevolod [243]
3 tens is 3 * 10 = 30
9 ones is 9 * 1 = 9
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3 years ago
Find the median, first quartile, third quartile, interquartile range, and any outliers for each set of data. 111, 68, 93, 88, 74
lilavasa [31]

Answer:

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

Step-by-step explanation:

Given the data:

111, 68, 93, 88, 74, 152, 119, 87, 88, 105, 84, 102, 151, 115, 112

Ordered data : 68, 74, 84, 87, 88, 88, 93, 102, 105, 111, 112, 115, 119, 151, 152

Sample size, n = 15

The first quartile, Q1 = 1/4(n+1)th term

Q1 = 1/4(15+1)th term

Q1 = 1/4(16) = 4th term

Q1 = 87

The Median , Q2 = 1/2(n+1)th term

Q2 = 1/2(15+1)th term

Q2 = 1/2(16) = 8th term

Q2 = 102

The third quartile, Q3 = 3/4(n+1)th term

Q3 = 1/4(15+1)th term

Q3 = 3/4(16) = 12th term

Q3 = 115

The interquartile range, IQR = Q3 - Q1

IQR = (115 - 87) = 28

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

4 0
3 years ago
Find the midpoint between two points on a coordinate plane whose coordinates are (5.7) and (-3, 1).
jok3333 [9.3K]

Answer:

(1,4)

Step-by-step explanation:

if~(x,y)~is~mid~point~of~(x_{1},y_{1})~and~ (x_{2},y_{2}~then\\x=\frac{x_{1}+x_{2}}{2} \\y=\frac{y_{1}+y_{2}}{2} \\x=\frac{5-3}{2} =\frac{2}{2}=1\\y=\frac{7+1}{2} =\frac{8}{2} =4

(x,y)→(1,4)

6 0
2 years ago
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