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3 years ago

A class 4 truck weighs between 14,000 and 16,000 pounds. What is weight range in tons?

1 answer:

7 0

The range is the highest value minus the lowest value.
16,000 - 14,000 = 2,000 pounds
1 ton is equal to 2,000 pounds so the weight range would be 1 ton

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18.4x-3.1=12.4x-16.9

Blababa [14]

Answer:

x=-2.3

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3 years ago

2,114 x 98 *100 points show work

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2 years ago

Loan a banko Q Mr shatish took of $ 12000 from The interest of for annum gives 5% per 3 years 3

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Answer:

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Step-by-step explanation:

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2 years ago

Test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students at the 0.005 signif

algol [13]

Answer:

a) F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

b) B. two-tailed

d) $t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64$

e) $p_v =P(t_{118}$

f) B. Reject the null hypothesis

Step-by-step explanation:

Information provided

$\bar X_{O}=2.91$ represent the mean for the Orange Coast

$\bar X_{C}=2.96$ represent the mean for the Coastline

$s_{O}=0.05$ represent the sample standard deviation for Orange Coast

$s_{C}=0.03$ represent the sample standard deviation for Coastline

$n_{O}=60$ sample size for Orange Coast

$n_{C}=60$ sample size for Coastline

$\alpha=0.005$ Significance level provided

t would represent the statistic

Part a

For this case we want to test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students

Null hypothesis: $\mu_{O} \geq \mu_{C}$

Alternative hypothesis: $\mu_{O} < \mu_{C}$

F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

Part b

For this case we need to conduct a left tailed test.

B. two-tailed

Part d

The statistic is given by:

$t=\frac{(\bar X_{O}-\bar X_{C})-\Delta}{\sqrt{\frac{s^2_{O}}{n_{O}}+\frac{s^2_{C}}{n_{C}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=60+60-2=118$

Replacing the info we got:

$t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64$

Part e

We can calculate the p value with this probability:

$p_v =P(t_{118}$

Part f

Since the p value is a very low value compared to the significance level given of 0.005 we can reject the null hypothesis.

B. Reject the null hypothesis

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2 years ago

Find the coordinates of the midpoint of a segment with the given endpoints W(-12, -7), T(-8, -4)

jasenka [17]

Finding the midpoint coordinates of any segment really boils down to finding the midpoints of each individual coordinate.

The x-coordinates of the two points are -12 and -8 - the number halfway between those two is -10, so that'll be the midpoint's x-coordinate. The y-coordinates are -7 and -4 - -5.5 is halfway between these two, so the y-coordinate will be 5.5.

Putting the two together, the midpoint of the segment WT has the coordinates (-10, -5.5).

4 0

3 years ago

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